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uranmaximum [27]
3 years ago
13

What is the change in oxidation number of sulfur when the dithionite anion, s2o42−, is converted to so2 in an oxidation-reductio

n reaction? does each sulfur atom gain or lose electrons in the reaction? is sulfur oxidized or reduced in the reaction?
Chemistry
1 answer:
Alisiya [41]3 years ago
6 0
1) In <span>dithionite anion (S</span>₂O₄²⁻) sulfur has oxidation number +3, because oxygen has oxidation number -2, so:
2 · x + 4 ·(-2) = -2.
2x = +6.
x = +3; oxidation number of sulfur.
In sulfur(IV) oxide (SO₂), sulfur has oxidation number +4, because oxygen is again -2 and compound has neutral charge:
x + 2 · (-2) = 0.
x = +4.
Change in sulfur is from +3 to +4.
Sulfur atoms lose electrons in the reaction. Sulfur is oxidized in the reaction, because his oxidation number raise from +3 to +4.
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32 g of sulphur contains 6.02×10²³ atoms.

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From the calculations made above, 5.59 g of sulphur contains 1.05×10²³ atoms.

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7 0
2 years ago
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