Answer:
magnitude: 100 N direction: east
Explanation:
The electrostatic force between two charges is given by

where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the charges
In this problem, we have



Substituting into the equation, we find the magnitude of the force

Concerning the direction, let's notice that:
- Both charges are positive, so the force between them is repulsive
- The charge q1 is west of the charge q2
- So, the force applied by q1 on q2 must be to the east (away from charge q1)
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Answer:
(1) 2 ohms
(2) 12 Volts Across each resistor
(3) I₁ = 3 A, I₂ = 2 A, I₃ = 1 A
Explanation:
From the question,
(1) Equilvalent Resistance (Rt) for parallel connection is
1/Rt =(1/R₁)+ (1/R₂) + (1/R₃)
Where R₁ = 4 ohms, R₂ = 6 ohms, R₃ = 12 ohms
1/Rt = 1/4 +1/6 +1/12
1/Rt = (3+2+1)/12
1/Rt = 6/12
1/Rt = 1/2
Rt = 2 ohms.
(2) Since the resistors are connected in parallel, They will have the same potential difference across them,
Hence the P.d across each resistor = 12 Volts.
(3) For R₁,
I₁ = V/R₁ = 12/4
I₁ = 3 A.
For R₂,
I₂ = V/R₂
I₂ = 12/6
I₂ = 2 A
For R₃,
I₃ = V/R₃
I₃ = 12/12
I₃ = 1 A