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3 years ago

14

What is the smallest possible piece an element in broken down into my normal laboratory processes

2 answers:

Gennadij [26K]3 years ago

6 0

i think the best answer for this question is B)

Zigmanuir [339]3 years ago

5 0

I think its letter b

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Phases of the moon. Help!???????

Veseljchak [2.6K]

Answer:

The Lunar Month.

New Moon.

Waxing Crescent Moon.

First Quarter Moon.

Waxing Gibbous Moon.

Full Moon.

Waning Gibbous Moon.

Third Quarter Moon.

Explanation:

6 0

2 years ago

Define the focus of a concave lens

Sophie [7]

Answer:

<u>Principal</u><u> </u><u>focus</u><u> </u><u>of</u><u> </u><u>concav</u><u>e</u><u> </u><u>lens</u><u> </u><u>-</u><u> </u>

★ The point at which rays parallel to principal axis coming from infinity appear to converge after being refracted from concave lens is called the principal focus of concave lens.

<em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em>

• <u>Additional</u><u> information</u><u> </u><u>-</u><u> </u>

★ Principal focus - A number of rays parallel to the principal axis after reflection from a concave mirror meet at a point on the principal axis or appear to come from a point after reflection from a convex mirror on the principal axis. This is called principal focus.

8 0

2 years ago

Which of the following pairs of terms directly relates to the actual brightness of a star?

Aloiza [94]

Answer:

D. absolute magnitude and apparent magnitude

7 0

2 years ago

Read 2 more answers

Please I need the answer right now will mark you brainliest

Dmitrij [34]

Answer:

Explanation:

what do u need help with

3 0

2 years ago

Read 2 more answers

A ball, which has a mass of 1.25 kg, is thrown straight up from the top of a building 225 meters tall with a velocity of 52.0 m/

Anastasy [175]

First we will find the speed of the ball just before it will hit the floor

so in order to find the speed of the cart we will first use energy conservation

$KE_i + PE_i = KE_f + PE_f$

$\frac{1}{2}mv_i^2 + mgh = \frac{1}{2}mv_f^2 + 0$

$\frac{1}{2}(1.25)(52)^2 + 1.25(9.8)(225) = \frac{1}{2}(1.25)v_f^2$

So by solving above equation we will have

$v_f = 84.3 m/s$

now in order to find the momentum we can use

$P = mv$

$P = 1.25 \times 84.3$

$P = 105.4 kg m/s$

3 0

3 years ago