The acceleration of the body in terms of the gravitational constant G is G.
According to Newton's law of universal gravitation;
F = Gm1m2/r^2
G = gravitational constant
m1 = mass of the first body
m2 = mass of the second body
r = distance between the two bodies
Substituting values to find the force on the two bodies;
F = G × 1 × 2/1^2
F = 2G
For the 2 Kg mass
F = ma
m = mass
a = acceleration
F = gravitational force
Hence,
2G = 2a
a = 2G/2
a = G
Learn more: brainly.com/question/13860566
Answer:
a = 8.951 m/s²
Explanation:
given,
angle = 0.52 radians
μ_s = 0.84
μ_k = 0.48
acceleration = ?
using
F + f = m a
mg sin θ + μk mg cos θ = m a
a = g sin θ + μk g cos θ
a = 9.8 x sin 0.52 + 0.48 x 9.8 x cos 0.52
a = 4.869 + 4.082
a = 8.951 m/s²
the magnitude of acceleration is a = 8.951 m/s²
Answer:
Higher.
Explanation:
The greater the frequency the bigger the amplitude gets and the greater pitch gets.
Think - more energy, bigger waves, more waves, and higher sound
Answer:
v = 4.10 10⁻³ m / s
Explanation:
For this exercise we will use Newton's second law where the force is magnetic
F -W = m a
As the field is directed to the north and the proton to the east, using the rule of the right hand the force is vertical upwards, the force balances the weight the acceleration is zero
F = W
q v B = m g
Let's calculate the speed
v = m g / (q B)
v = 1,673 10⁻²⁷ 9.8 / (1.6 10⁻¹⁹ 2.5 10⁻⁵)
v = 4.10 10⁻³ m / s
