Question

Write the equilibrium‑constant expression for the reaction A ( s ) + 3 B ( l ) − ⇀ ↽ − 2 C ( aq ) + D ( aq ) in terms of [ A ] , [ B ] , [ C ] , and [ D ] , as needed. Note that K c , which is sometimes symbolized as K eq , denotes that the equilibrium constant is expressed using molar concentrations. For this question, K c means the same thing as K eq .

Answer 1

Answer: The expression of equilibrium constant is $K_{eq}=[C]^2\times [D]$

Explanation:

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

For a general chemical reaction:

$aA+bB\rightleftharpoons cC+dD$

The expression for $K_{eq}$ is written as:

$K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

Concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

$A(s)+3B(l)\rightleftharpoons 2C(aq.)+D(aq.)$

The expression of $K_{eq}$ for above equation follows:

$K_{eq}=[C]^2\times [D]$

Hence, the expression of equilibrium constant is $K_{eq}=[C]^2\times [D]$