Spaceship 1 and spaceship 2 have equal masses of 150kg. Spaceship 1 has the speed of 0 m/s and spaceship 2 has a speed of 6 m/s.
1 answer:
Answer:
3 m/s
Explanation:
The computation of speed is shown below:-
We will compute the equation by using the law of conservation of momentum; also, the total momentum prior and following the collision must be conserved. Therefore we can write the equation is the following manner:-
where the symbols represent
150 kg is the mass of spaceship 1 = m1
150 kg is the mass of spaceship 2 = m2
0 m/s is the initial velocity of spaceship 1 = u1
6 m/s is the initial velocity of spaceship 2 = u2
and v is the velocity of the 2 ships so that they can collide and combined together
For v we will get the following equation to reach the speed
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Answer:
E) 6.5 A
Explanation:
Given that
L = 40 m H
C= 1.2 m F
Maximum charge on capacitor ,Q= 45 m C
The maximum current I given as
I = Q.ω
ω =angular frequency
By putting the values
ω = 144.33 rad⁻¹
Maximum current
I = 45 x 10⁻³ x 144.33 A
I= 6.49 A
I = 6.5 A
E) 6.5 A
Answer:
x=0.53
Explanation:
Using Gauss law the field is uniform so
E=ζ/ε
Charge densities ⇒ζ=1.
ε=8.85
Force of charge is
So finally knowing the acceleration and the time the distance can be find using equation of uniform motion
Answer:
Explanation:
From frequency of oscillation
Initially with the suspended string, the above equation is correct for the relation, hence
where k is force constant and m is the mass
When the spring is cut into half, by physics, the force constant will be doubled as they are inversely proportional
Employing f2/ f1, we have