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vladimir1956 [14]
3 years ago
10

A short current element dl⃗ = (0.500 mm)j^ carries a current of 4.80 A in the same direction as dl⃗ . Point P is located at r⃗ =

(-0.730 m)i^+ (0.390m)k^. Find the magnetic field at P produced by this current element. Enter the x, y, and z components of the magnetic field in Teslas separated by commas.
Physics
1 answer:
sammy [17]3 years ago
7 0

Answer:

Magnetic field in Tesla: 1.65*10^−10 T,   0,   3.09*10^−10 T

Explanation:

Given data:

i = 4.8 A ,

dBx = 1.65*10^-10 T

dBy = 0 T

dBz = 3.09 * 10^-10 T

Attached below is the detailed solution

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A uniform solid sphere has mass m= 7 kg and radius r= 0. 4 m. What is its moment of inertia about an axis tangent to its surface
lilavasa [31]

The moment of inertia of a uniform solid sphere is equal to 0.448 kgm^2.

<u>Given the following data:</u>

Mass of sphere = 7 kg.

Radius of sphere = 0.4 meter.

<h3>How to calculate moment of inertia.</h3>

Mathematically, the moment of inertia of a solid sphere is given by this formula:

I=\frac{2}{5} mr^2

<u>Where:</u>

  • I is the moment of inertia.
  • m is the mass.
  • r is the radius.

Substituting the given parameters into the formula, we have;

I=\frac{2}{5} \times 7 \times 0.4^2\\\\I=2.8 \times 0.16

I = 0.448 kgm^2.

Read more on inertia here: brainly.com/question/3406242

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A chevrolet corvette convertible can brake to a stop from a speed of 60.0 mi/h in a distance of 123 ft on a level roadway. what
pychu [463]
By definition we have that the final speed is:
 Vf² = Vo² + 2 * a * d
 Where,
 Vo: Final speed
 a: acceleration
 d: distance.
 We cleared this expression the acceleration:
 a = (Vf²-Vo²) / (2 * d)
 Substituting the values:
 a = ((0) ^ 2- (60) ^ 2) / ((2) * (123) * (1/5280))
 a = -77268 mi / h ^ 2
 its stopping distance on a roadway sloping downward at an angle of 17.0 ° is:
 First you must make a free body diagram and see the acceleration of the car:
 g = 32.2 feet / sec ^ 2
 a = -77268 (mi / h ^ 2) * (5280/1) (feet / mi) * (1/3600) ^ 2 (h / s) ^ 2
 a = -31.48 feet / sec ^ 2
 A = a + g * sin (θ) = -31.48 + 32.2 * sin17.0
 A = -22.07 feet / sec ^ 2
 Clearing the braking distance:
 Vf² = Vo² + 2 * a * d
 d = (Vf²-Vo²) / (2 * a)
 Substituting the values:
 d = ((0) ^ 2- (60 * (5280/3600)) ^ 2) / (2 * (- 22.07))
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5 0
3 years ago
Read 2 more answers
the time required for one cycle, a complete motion that returns to its starting point, it called the_____. period medium frequen
Salsk061 [2.6K]

Answer:

The time required for one cycle, a complete motion that returns to its starting point,it is called periodic motion

Explanation:

I hope this will help you:)

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3 years ago
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