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vladimir1956 [14]
3 years ago
10

A short current element dl⃗ = (0.500 mm)j^ carries a current of 4.80 A in the same direction as dl⃗ . Point P is located at r⃗ =

(-0.730 m)i^+ (0.390m)k^. Find the magnetic field at P produced by this current element. Enter the x, y, and z components of the magnetic field in Teslas separated by commas.
Physics
1 answer:
sammy [17]3 years ago
7 0

Answer:

Magnetic field in Tesla: 1.65*10^−10 T,   0,   3.09*10^−10 T

Explanation:

Given data:

i = 4.8 A ,

dBx = 1.65*10^-10 T

dBy = 0 T

dBz = 3.09 * 10^-10 T

Attached below is the detailed solution

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PLZ HELP WILL GIVE BRAINLIEST
xxTIMURxx [149]

Answer:

12.7m/s

Explanation:

Given parameters:

Mass of the diver = 77kg

Height  = 8.18m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we use one of the motion equations.

            v²  = u² + 2gh

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

h is the height

             v² = 0² + (2 x 9.8 x 8.18)

             v² = 160.3

             v = 12.7m/s

7 0
3 years ago
A seesaw pivots as shown in below. What is the net torque about the pivot point?
rodikova [14]

Answer:

2.3 Nm clockwise

Explanation:

Take counterclockwise to be positive and clockwise to be negative.

∑τ = (3 N) (2.5 m) − (7 N) (1.4 m)

∑τ = 7.5 Nm − 9.8 Nm

∑τ = -2.3 Nm

The net torque is 2.3 Nm clockwise.

7 0
3 years ago
The first law of thermodynamics states that energy can neither be created nor destroyed. If this is true then why are we always
riadik2000 [5.3K]

Answer:

The second law of thermodynamics states in an isolated system, the entropy (the amount of thermal energy that cannot be converted into mechanical work, also known as the amount of disorder) always increases, therefore, an isolated system always require an external input (new sources) of energy for there to be orderliness or for the available energy of the system to remain constant or increase

Explanation:

5 0
2 years ago
Please someone do this <br>please ​
monitta

The various contributions involved till the chapati is made is given below.

<h3>What is food?</h3>

The substance that we intake for the body to charge up by giving nutrients is called the food.

Wheat is a staple food. We make chapati from flour obtained from the wheat grains.

The various contributions involved till the chapati is made is given below.

                 Take required amount of atta in a container

                                                     ↓

                    Add water accordingly to form a dough

                                                     ↓

                 Apply oil to make dough smooth for long time

                                                    ↓

        Take small dough, make it a ball shaped and apply dry flour

                                                    ↓

               Roll it using rolling pin on the chapati maker plate

                                                    ↓

      After making it circular or any shape you want, place it on hot tawa

                                                    ↓

                               Bake it on both the sides

                                                   ↓

                                      Chapati is ready

Thus, the flow chart is made.

Learn more about food.

brainly.com/question/16327379

#SPJ1

6 0
2 years ago
As a science fair project, you want to launch an 800 g model rocket st raight up and hit a horizontally moving target as it pass
fredd [130]

Sum the forces in the y (upward) direction

\sum F_y = ma

F_t +F_w = ma

15N - (0.800kg)(9.81m/s^2) = 0.800kg * a

a = 8.94 m/s^2

Applying the kinematic equations of linear motion we have that the displacement as a function of the initial speed, acceleration and time is

s = v_0t + \frac{1}{2} at^2

30 = 0 +\frac{1}{2} (8.94) t^2

t = 2.59 s

Again through the kinematic equation of linear motion that describes velocity as the change of displacement in a given time, we have to

v = \frac{d}{t} \rightarrow d = vt

d = (15m/s)(2.59s)

d = 38.85m

Therefore the horizontal distance between the target and the rocket should be 38.83m

4 0
3 years ago
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