A short current element dl⃗ = (0.500 mm)j^ carries a current of 4.80 A in the same direction as dl⃗ . Point P is located at r⃗ =
1 answer:
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Answer with Step-by -step explanation:
We are given that
b.
below the positive x-axis
Therefore, the angle made by vector A in counter clockwise direction when measure from positive x-axis=
x-component of vector A=
y-Component of vector A=
Magnitude of vector B=86 m
The vector B makes angle with positive x- axis=
x-component of vector B=
y-Component of vector B=
Vector A=
Vector B=
Vector C=A+B
Substitute the values
c.Direction=
The direction of the vector C=21.5 degree
Answer:
(a) The current should be in opposite direction
(b) The current needed is 39.8 A
Explanation:
Part (a)
Based, on right hand rule, the current should be in opposite direction
Part (b)
given;
strength of magnetic field, B = 370 µT
distance between the two parallel wires, d = 8.6 cm
At the center, the magnetic field strength is twice
R = d/2 = 8.6/2 = 4.3 cm = 0.043 m
Therefore, current needed is 39.8 A