Fission reactions can get out of control without neutron moderation. The correct option among all the options that are given in the question is the fourth option or option "D". The other options in this question can be discarded. I hope that this is the answer that you were looking for and it has come to your help.
O3 + M2+(aq) + H2O(l) => O2(g) + MO2(s) + 2 H+
Eo(cell) = Eo(O3/O2) - Eo(MO2/M2+)
0.44 = 2.07 - Eo(MO2/M2+)
Eo(MO2/M2+) = 1.59 V
Explanation:
It is known that for high concentration of 
, reduction will take place. As, cathode has a positive charge and it will be placed on left hand side.
Now, 
= 0 and the general reaction equation is as follows.
3.00 M n = 2 30 mM
E = 
= 
= 0.038 V
Therefore, we can conclude that voltage shown by the voltmeter is 0.038 V.
Answer:
optical (optic is the word used for referring to the eye ie optic nerve)
Explanation:
