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4 years ago

Hamish is studying what happens when he sends a sound

Physics

2 answers:

horrorfan [7]4 years ago

6 0

Wave 3 will move the slowest, the statement could made about the data collected in Hamish's table

Answer: Option C

<u>Explanation: </u>

Sound waves require medium to pass from one to another. Depending upon the density of molecules in the medium, the speed of the sound waves can be determined. As we know that compression and rarefactions will be formed for propagation of sound waves when the waves collide with molecules of the medium.

So, if there is less molecules present in the medium or loosely packed molecules present in the medium with high mean free path length than the sound wave will be travelling slowly in that medium.

Thus, as we known that gas has the loosely packed molecules among the other states of matter, so wave 3 which is made to pass through the gas medium will be propagation at the lowest speed or will move the slowest compared to other 3 gases made to propagate in solid and liquid mediums.

Anestetic [448]4 years ago

4 0

Answer:

Explanation:

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A satellite that goes around the earth once every 24 hours iscalled a geosynchronous satellite. If a geosynchronoussatellite is

alexgriva [62]

Answer:

R=4.22*10⁴km

Explanation:

The tangential speed $v$ of the geosynchronous satellite is given by:

$v=\frac{2\pi R}{T}$

Because $2\pi R$ is the circumference length (the distance traveled) and T is the period (the interval of time).

Now, we know that the centripetal force of an object undergoing uniform circular motion is given by:

$F_c=\frac{mv^{2} }{R}$

If we substitute the expression for $v$ in this formula, we get:

$F_c=\frac{m(\frac{2\pi R}{T})^{2}}{R}=\frac{4m\pi ^{2}R}{T^{2}}$

Since the centripetal force is the gravitational force $F_g$ between the satellite and the Earth, we know that:

$F_g=\frac{GMm}{R^{2}}\\\\\implies \frac{GMm}{R^{2}}=\frac{4m\pi ^{2}R}{T^{2}}\\\\R^{3}=\frac{GMT^{2}}{4\pi^{2}} \\\\R=\sqrt[3]{\frac{GMT^{2}}{4\pi^{2}} }$

Where G is the gravitational constant ( $G=6.67*10^{-11} Nm^{2}/kg^{2}$ ) and M is the mass of the Earth ( $M=5.97*10^{24}kg$ ). Since the period of the geosynchronous satellite is 24 hours (equivalent to 86400 seconds), we finally can compute the radius of the satellite:

$R=\sqrt[3]{\frac{(6.67*10^{-11}Nm^{2}/kg^{2})(5.97*10^{24}kg)(86400s)^{2}}{4\pi^{2}}}\\\\R=4.22*10^{7}m=4.22*10^{4}km$

This means that the radius of the orbit of a geosynchronous satellite that circles the earth is 4.22*10⁴km.

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3 years ago

Determine the current I flowing through a solenoid, if the magnetic flux inside its core is found to be 1.30 10-4 Wb. The radius

inna [77]

Answer: The current I flowing through a solenoid is 11.6A

Explanation: Please see the attachments below

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3 years ago

It is easier to drive In sharp nails in a piece of wood than the blunt ones why?

murzikaleks [220]

The sharp nail has a less surface area in comparison to a blunt nail and pressure is inversely proportional to area so it is easier to Hamer a sharp nail into a wood rather than having a blunt nail in wood

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3 years ago

What is the name of the chart that contain elements?

prisoha [69]

Answer:

Element Chart

Explanation:

It is a chart that provides many different elements.

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3 years ago

Two 6 ohm resistors in parallel gives an equivalent resistance of

Mashcka [7]

Answer:

3 ohms

Explanation:

6×6/6+6 =3 .............

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3 years ago