Neutron star: a newly formed neutron star can have a temperature of about 10^11 Kelvin to 10^12 Kelvin, but it can drop to 10^6 Kelvin. Its brightness is a million times fainter than the sun's brightness because of its size and distance from a point of view.
Dwarf star: Yellow dwarfs are small, main sequence star. <span>Red dwarfs are the most common type of star, </span>it's a small, cool, very faint, main sequence star whose surface temperature is under about 4,000 K.
Main sequence: has a temperature of about 10 million K. Its luminosity depends on the size and the mass of the star.
Red Giant: not normally as bright as the main sequence but it can create 1,000 to 10,000 times the luminosity that the sun gives off. The outer atmosphere is inflated, making the surface temperature to be as low as 5,000 K.
Supergiant: These stars have very "cool" surface temperatures that can range between 3500 and 4500 K (more or less). Depending on proximity, size, and mass, their luminosity can be either very high or very dim... though, they are normally very large stars.
Hope this helped!
The molecules in liquid water are held together by relatively strong hydrogen bonds and its enthalpy of vaporization, 40.65 kJ/mol is more than five times the energy required to heat the same quantity of water from: 0 °C to 100 °C (cp = 75.3 J K−1 mol−1).
Hope this helps.
Explanation:
For what I can see, is missing the concentration of [Ag+] in the half-cell. To calculate it:
Niquel half-cell
Oxidation reaction: 
![E=E^0 - \frac{R*T}{n*F}*ln(1/[Ni^{2+}])](https://tex.z-dn.net/?f=E%3DE%5E0%20-%20%5Cfrac%7BR%2AT%7D%7Bn%2AF%7D%2Aln%281%2F%5BNi%5E%7B2%2B%7D%5D%29)
Assuming T=298 K / R=8.314 J/mol K / F=96500 C
Silver half-cell
Reduction reaction: 
![E=E^0 - \frac{R*T}{n*F}*ln(1/[Ag+])](https://tex.z-dn.net/?f=E%3DE%5E0%20-%20%5Cfrac%7BR%2AT%7D%7Bn%2AF%7D%2Aln%281%2F%5BAg%2B%5D%29)
Assuming T=298 K / R=8.314 J/mol K / F=96500 C
![0.835V=0.8V - \frac{8.314*298}{1*96500}*ln(1/[Ag+])](https://tex.z-dn.net/?f=0.835V%3D0.8V%20-%20%5Cfrac%7B8.314%2A298%7D%7B1%2A96500%7D%2Aln%281%2F%5BAg%2B%5D%29)
![[Ag+]=0.26 M](https://tex.z-dn.net/?f=%5BAg%2B%5D%3D0.26%20M)
Answer : The mass of 
precipitate produced will be, 9.681 grams.
Explanation : Given,
Molarity of NaI = 0.210 M
Volume of solution = 0.2 L
Molar mass of = 461.01 g/mole
First we have to calculate the moles of 
.
Now we have to calculate the moles of .
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 moles of react to give 1 mole of
So, 0.042 moles of react to give 
moles of
Now we have to calculate the mass of .
Therefore, the mass of precipitate produced will be, 9.681 grams.
Angles do not change they can only rotate in a circular motion if the angles in a 30°−60°−90° triangle after it is rotated clockwise at 45°.
<h3>What are the angles?</h3>
The angles are the distance between two lines that are attached at one point and they can vary in shapes like triangle and square or circle and rectangle.
The square has the handle of equality for all the sides rectangle has two opposite side angles equal and the circle It has only one angle triangle consisting of 3 angles which are fixed and cannot be changed.
Therefore, if the angles in a 30°−60°−90° triangle after it is rotated clockwise at 45°Angles do not change they can only rotate in a circular motion.
Learn more about angles, here:
brainly.com/question/14569348
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