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natali 33 [55]
3 years ago
14

Zn(s), Zn(NO3)2 (0.30 M) || Ag(s), AgNO3 (0.010 M) 1. Draw the schematic of the electrochemical cell that you created including

all the components (metals, solutions, salt bridges, voltmeters, etc.) in this portion of the experiment. Annotate on the schematic which side is the anode, which side is the cathode, the sign of each half cell, the composition of the metals and solutions, and the direction of the flow of the electrons through the cell.
Chemistry
1 answer:
snow_lady [41]3 years ago
7 0

Answer:

Do it yourself

Explanation:

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If 20 grams of zinc reacts with hydrochloric acid, how much zinc chloride is produced?
Oksi-84 [34.3K]
Assuming there is excess acid, the equation for the reaction is Zn + 2HCl -> ZnCl2 + H2.
Mols of zinc = 20/65 (mass/relative atomic mass)
Ratio of Zn : ZnCl2 = 1 : 1
Hence mols of Zinc = mols of Zinc chloride
Mass of ZnCl2 = (20/65)(65+71)
= 41.8g
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What is abbreviated structural formula of the 2-metil-5-isopropiloctan?​
Alja [10]

Answer:

            CH3

            |

CH3-    C H  -CH2-CH2-      CH   - CH2-CH2-CH3

                                              |

                                              CH

                                           /     \

                                         CH3  CH3

Explanation:

Octan

C-C-C-C-C-C-C-C

Metyl

CH3 -

Isopropyl

     CH3

    /

- CH

   \

     CH3

2-metil-5-isopropiloctan

           CH3

            |

CH3-    C H  -CH2-CH2-      CH   - CH2-CH2-CH3

                                              |

                                              CH

                                           /     \

                                         CH3  CH3

                           

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WHICH VIRAL REPRODUCTION CYCLE HAD THE VIRUS PUTTING ITS GENETIC MATERIAL INTO THE CELL
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Which is a process that causes an organism’s poorly suited characteristics to disappear?
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4 0
3 years ago
In acidic solution, the sulfate ion can be used to react with a number of metal ions. One such reaction is SO42−(aq)+Sn2+(aq)→H2
allsm [11]

Answer:

The final balanced equation is :

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

Explanation:

SO_4^{2-}(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+Sn^{4+}(aq)

Balancing in acidic medium:

First we will determine the oxidation and reduction reaction from the givne reaction :

Oxidation:

Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)

Balance the charge by adding 2 electrons on product side:

Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)+2e^-....[1]

Reduction :

SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)

Balance O by adding water on required side:

SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)

Now, balance H by adding H^+ on the required side:

SO_4^{2-}(aq)+4H^+(aq)\rightarrow H_2SO_3(aq)+H_2O(l)

At last balance the charge by adding electrons on the side where positive charge is more:

SO_4^{2-}(aq)+4H^+(aq)+2e^-\rightarrow H_2SO_3(aq)+H_2O(l)..[2]

Adding [1] and [2]:

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

The final balanced equation is :

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

4 0
3 years ago
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