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Mademuasel [1]
3 years ago
9

An average human weighs about If two such generic humans each carried 1.0 coulomb of excess charge, one positive and one negativ

e, how far apart would they have to be for the electric attraction between them to equal their weight?
Physics
1 answer:
Virty [35]3 years ago
3 0

Answer:

Explanation:

excess charge, q1 = 1 C, q2 = - 1 C

Let the distance is r.

let your mass is, m = 50 kg

Weight, W = mass x gravity = 50 x 9.8 = 490 N

Use the Coulomb's law

F=k\frac{q_{1}q_{2}}{r^{2}}

490 = \frac{9\times10^{9}\times 1\times 1}{r^{2}}

r = 4285.7 m

r = 4.285 km

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What could you do to change the volume of a gas?
denis23 [38]
There are a number of ways you can change the volume of a gas.

Temperature: if you heat the gas it rises causing a change volume because the electrons gain more thermal energy BUT if you cool the gas down it sinks decreasing the molecules (the opposite effect)

Pressure can also change a gases volume. high pressure forces the molecules together creating a solid (along with cold temperatures)

Hope this helps!
5 0
4 years ago
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An airplane flies in a horizontal circle of radius 500 m at a speed of 150 m/s. If the radius were changed to 1000 m, but the sp
laila [671]

Answer:

The centripetal acceleration changed by a factor of 0.5

Explanation:

Given;

first radius of the horizontal circle, r₁ = 500 m

speed of the airplane, v = 150 m/s

second radius of the airplane, r₂ = 1000 m

Centripetal acceleration is given as;

a = \frac{v^2}{r}

At constant speed, we will have;

v^2 =ar\\\\v = \sqrt{ar}\\\\at \ constant\ v;\\\sqrt{a_1r_1} = \sqrt{a_2r_2}\\\\a_1r_1 = a_2r_2\\\\a_2 = \frac{a_1r_1}{r_2} \\\\a_2 = \frac{a_1*500}{1000}\\\\a_2 = \frac{a_1}{2} \\\\a_2 = \frac{1}{2} a_1

a₂ = 0.5a₁

Therefore, the centripetal acceleration changed by a factor of 0.5

7 0
4 years ago
If the evaporator outlet temperature on an r410A system is 50f and the evaporator superheat is 10f, what is the evaporating pres
Olenka [21]

Answer:

So, the evaporating pressure of the R410A = 118 psig

Explanation:

Solution:

For R410A system:

Data Given:

Evaporator Outlet Temperature = 50°F

Evaporator Superheat = 10°F

Required:

Evaporating Pressure in the system = ?

For this, first of all, we need to calculate inlet temperature on R410A system from the given value of outlet temperature.

Evaporator inlet temperature is the difference of outlet temperature and evaporator superheat.

Evaporator inlet temperature = Outlet Temperature - Evaporator Superheat

Evaporator inlet Temperature = 50°F - 10°F

Evaporator inlet Temperature = 40°F

Now, as we have the inlet temperature and the R410A system. We can consult the pressure temperature chart or PT chart, which I have attached and highlighted the value of evaporating pressure for 40°F inlet temperature.

So, the evaporating pressure of the R410A = 118 psig

3 0
3 years ago
Define valence electrons
lisabon 2012 [21]

Answer:

In chemistry and physics, a valence electron is an outer shell electron with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed; in a single covalent bond, both atoms in the bond contribute one valence electron in order to form a shared pair.

Explanation:

3 0
4 years ago
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A car accelerates for 10 seconds. During this time, the angular
bagirrra123 [75]

Answer:

the angular acceleration of the car is 1.5 rad/s²

Explanation:

Given;

initial angular velocity, \omega_i = 10 rad/s

final angular velocity, \omega_f = 25 rad/s

time of motion, t = 10 s

The angular acceleration of the car is calculated as follows;

a_r = \frac{\omega_f - \omega_i }{t} \\\\a_r = \frac{25-10}{10} = 1.5 \ rad/s^2

Therefore, the angular acceleration of the car is 1.5 rad/s²

4 0
3 years ago
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