All categories

4 years ago

HELP ASAP PLZ

Physics

1 answer:

attashe74 [19]4 years ago

5 0

Answer:

Increases

Explanation:

Because acceleration goes higher

You might be interested in

Select the correct answer

Nadya [2.5K]

Answer:

$f= 3.0 \times 10 {}^{8} \div 7.0 \times 10 {}^{7} \\ f = 4.28hz$

Given

7 0

3 years ago

The frequency of the applied RF signal used to excite spins is directly proportional to the magnitude of the static magnetic fie

telo118 [61]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The uncertainty in inverse frequency is $\Delta [\frac{1}{w} ]= \frac{3}{2000} \ s$

Explanation:

From the question we are told that

The value of the proportionality constant is $k = 5 \frac{Hz }{T}$

The strength of the magnetic field is $B = 20 \ T$

The change in this strength of magnetic field is $\Delta B = 3 \ T$

The magnetic field is given as

$B = \frac{k}{\frac{1}{w} }$

Where $w$ is frequency

The uncertainty or error of the field is given as

$\Delta B = \frac{k }{[\frac{1}{w}^]^2 } \Delta [\frac{1}{w} ]$

The uncertainty in inverse frequency is given as

$\Delta [\frac{1}{w} ] = \frac{\Delta B}{k [\frac{1}{w^2} ]}$

$\Delta [\frac{1}{w} ]= \frac{\Delta B}{k (B)^2 }$

substituting values

$\Delta [\frac{1}{w} ]= \frac{3}{5 (20)^2 }$

$\Delta [\frac{1}{w} ]= \frac{3}{2000} \ s$

6 0

3 years ago

Find the first three harmonics of a string of linear mass density 2.00 g/m and length 0.600 m when the tension in it is 50.0 n.

blsea [12.9K]

As we know that Nth harmonic of the string is given by

$f = \frac{N}{2L}\sqrt{\frac{T}{m/L}}$

now here we will have

$m/L = mass density = 2 g/m$

$m/L = 0.002 kg/m$

$Length = L = 0.600 m$

$Tension = T = 50.0 N$

now from above formula we have

$f = \frac{N}{2(0.600)}\sqrt{\frac{50.0}{0.002}}$

$f = 131.8N$

now for first harmonic N = 1

$f_1 = 131.8 Hz$

for second harmonic N = 2

$f_2 = 263.5 Hz$

for third harmonic N = 3

$f_3 = 395.3 Hz$

8 0

4 years ago

3. A car moves from rest with uniform acceleration along a horizontal road. After travelling a distance of 100 metres, it has ki

mrs_skeptik [129]

Explanation:

Given Data :

▪ Initial velocity = zero ( body is at rest)

▪ Distance travelled = 100m

▪ Final kinetic energy = 200000J

To Find :

▪ Resultant force acting on the car.

Therefore:

W = F × d = ΔK ----------------- eq 1.

where,

W = work done

F = applied force

d = distance

ΔK = change in kinetic energy

Calculation :

→ F × d = Kf - Ki ----------------- eq 2.

Where:

Kf = Final kinetic energy = 200000

Ki = initial kinetic energy = 0

Substituting our values into the formula from equation (2)

→ F × 100 = 200000 - 0

→ F = 200000/100

→ F = 2000N

8 0

3 years ago

An atom that has 7 protons 7 electrons and 6 neutrons

defon

The atom carbon is the answer

3 0

3 years ago

Read 2 more answers