A boy eat a energy of a sandwich to run a race because when they eat a sandwich it helps them to help it mid workout and real nutritions of NYC and bring extra fuel and eating the right thing
I hope this help
Answer:
A(t) = 160 - 130 e^(-t/40)
Explanation:
At the start, the tank contains A(0) = 30 g of salt.
Salt flows in at a rate of
(1 g/L) * (4 L/min) = 5 g/min
and flows out at a rate of
(A(t)/160 g/L) * (4 L/min) = A(t)/40 g/min
so that the amount of salt in the tank at time t changes according to
A'(t) = 4 - A(t)/40
Solve the ODE for A(t):
A'(t) + A(t)/40 = 4
e^(t/40) A'(t) + e^(t/40)/40 A(t) = 4e^(t/40)
(e^(t/40) A(t))' = 4e^(t/40)
e^(t/40) A(t) = 160e^(t/40) + C
A(t) = 160 + Ce^(-t/40)
Given that A(0) = 30, we find
30 = 160 + C
C = -130
so that the amount of salt in the tank at time t is
A(t) = 160 - 130 e^(-t/40)
i cant solve this but good question
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