Answer:
Explanation:
Let 100 m/s be the velocity of projection.
So horizontal component
= 100 cos42
= 74.31 m /s
Vertical component = - 100 sin 42 . in upward direction
66.91 m/s
Net displacement = 2.1 downwards ( + ve )
Using s = ut + 1/2 gt²
2.1 = - 66.91 t + .5 x 9.8 x t²
4.9 t² - 66.91 t - 2.1 = 0
t = 13.685 s
Horizontal distance covered
= 13.685 x 74.31
= 1016.93 m
If angle of projction is 40°
So horizontal component
= 100 cos40
= 76.60 m /s
Vertical component = - 100 sin 42 . in upward direction
64.27 m/s
Net displacement = 2.1 downwards ( + ve )
Using s = ut + 1/2 gt²
2.1 = -76.60 t + .5 x 9.8 x t²
4.9 t² - 76.60 t - 2.1 = 0
t = 15.659 s
Horizontal distance covered
= 15.659 x 76.60
= 1199.49 m
So horizontal range is increased , if angle of projection is increased .
I would think 2.759kmockinbirds if you consider mockingbirds equal to a metre and kmockinbird to kilometres
Answer:
They wishin' on me, yuh
I been movin' calm, don't start no trouble with me
Tryna keep it peaceful is a struggle for me
Don't pull up at 6 AM to cuddle with me
You know how I like it when you lovin' on me
I don't wanna die for them to miss me
Yes, I see the things that they wishin' on me
Hope I got some brothers that outlive me
They gon' tell the story, shYit was different with me
Explanation:
Answer:
a )
Density = mass / volume
= 3500 / 3.5
= 1000 kg m⁻³
b) gauge pressure = h d g
h is height of water column
d is density
g is acceleration due to gravity
Put the values in the equation above
Gauge pressure = .15 x 1000 x 9.8
= 1470 Nm⁻²
Atmospheric pressure = 100000 Nm⁻²
Total pressure
= 101470 N m⁻²
c ) Volume of water displaced = volume of object
= 55 x 10⁻⁶ m³
Buoyant Force = weight of displaced water
= 55 x 10⁻⁶ x 1000 x 9.8
= .539 N.
