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Tju [1.3M]
3 years ago
15

What became stuck on the turtle's legs before it crossed the highway?

Physics
2 answers:
Kryger [21]3 years ago
7 0
Wild Oat Seeds is the answer (according to answers website)
spin [16.1K]3 years ago
5 0
The correct answer for your question "Wild Oat Seeds"
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A segment of wire carries a current of 25 A along the x axis from x = −2.0 m to x = 0 and then along the y axis from y = 0 to y
Rashid [163]

Answer: F = 2N

Explanation: If a current i is flowing in a wire of length L lying in a region of magnetic field B, then the magnetic force acting on the wire is given by

F = BIL

Please find the attached file for the solution

8 0
3 years ago
Rahul sits in a chair reading a book. Which force is equal to the force Rahul exerts on Earth?
Mademuasel [1]
The first opiton is the answer A)<span>Rahul’s weight
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8 0
3 years ago
Read 2 more answers
While doing a lab, a student found the density of a piece of pure aluminum to be 2.85 g/cm3. The accepted value for the density
bezimeni [28]
The equation for percent error is

% Error = 100*|Experimental-Theoretical|/Theoretical

Our experimental is 2.85g/cm^3 and the accepted is 2.7g/cm^3

Thus our % Error = 5.555%
3 0
3 years ago
Estimate the smallest possible period of a satellite in a circular orbit around earth. (mass and radius of earth is 5.98 x 1024
myrzilka [38]
Given: Mass of earth Me = 5.98 x 10²⁴ Kg

           Radius of earth r = 6.37 x 10⁶ m

            G = 6.67 x 10⁻¹¹ N.m²/Kg²

Required: Smallest possible period T = ?

Formula: F = ma;  F = GMeMsat/r²     Centripetal acceleration ac = V²/r

               but V = 2πr/T

equate T from all equation.

F = ma

GMeMsat/r² = Msat4π²/rT²    

GMe = 4π²r³/T²

T² = 4π²r³/GMe  

T² = 39.48(6.37 x 10⁶ m)³/6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)

T² = 1.02 x 10²² m³/3.99 x 10¹⁴ m³/s²

T² = 25,563,909.77 s²

T = 5,056.08 seconds    or around   1.4 Hour

3 0
3 years ago
A 17926-lb truck enters an emergency exit ramp at a speed of 75.6 ft/s. It travels for 6.4 s before its speed is reduced to 30.3
I am Lyosha [343]

Answer:

F_{braking}=337299 pdl

Explanation:

Impulse-Momentum relation:

I=\Delta p\\ F_{total}*t=m(v_{f}-v{o})

F_{total}=-F_{braking}+mgsin{\theta}

We solve the equations in order to find the braking force:

F_{braking}=m(v_{o}-v{f})/t+mgsin{\theta}=17926(75.6-30.3)/6.4+17926*32.17*sin21.4=337299 pdl

6 0
3 years ago
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