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3 years ago

The useful power output of the engine is 2.0 kw. Calculate the rate at which energy is absorbed from the hot reservoir.

Physics

1 answer:

Alika [10]3 years ago

3 0

Answer:

2000 J per second or 2kJ per second.

Explanation:

The definition for power (W) is the rate of energy (J) per unit of time (seconds). In this case the power output is 2kW, or 2000W. This means the energy rate of the engine must be 2000 joules per second, or 2kJ per second.

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Which of the following statements about electric field lines associated with electric charges is false? Electric field lines can

Tcecarenko [31]

Answer:

The false statement is 'Electric field lines form closed loops'.

Explanation:

Electric field lines originate from positive end and terminates at negative end,i.e., field lines are inward in direction to the negative charges and outward from the positive charges.
These lines when close together represents high intensity and when far apart shows low intensity of the field.
These lines do not intersect, as the tangent drawn on these lines provides us with the field direction and intersection of these lines means two field directions which is not possible.
These lines unlike magnetic field lines do not form closed loops as they do not turn around but originate at positive end and terminates at negative end which ensures no loop formation.

8 0

3 years ago

Do we include signs if we calculate Electric field strength?

expeople1 [14]

Yes because if not people wouldn't understand how did you calculate electric field strength.

6 0

2 years ago

What is another name for the introitus? psych 230?

Vera_Pavlovna [14]

Vaginal opening. areola is the part of the breast.

7 0

3 years ago

A projector is placed on the ground 22 ft. away from a projector screen. A 5.2 ft. tall person is walking toward the screen at a

Stella [2.4K]

Answer:

y = 67.6 feet, y = 114.4/ (22 - 3t)

Explanation:

For this exercise let's use that light travels in a straight line and some trigonometric relationships, the symbols are in the attached diagram

Large triangle Projector up to the screen

tan θ = y / L

For the small triangle. Projector up to the person

tan θ = y₀ / (L-d)

The angle is the same, so we equate the two equations

y₀ / (L -d) = y / L

y = y₀ L / (L-d)

The distance from the screen (d), we look for it with kinematics

v = d / t

d = v t

we replace

y = y₀ L / (L - v t)

y = 5.2 22 / (22 - 3 t)

y = 114.4 (22 - 3t)⁻¹

This is the equation of the shadow height change as a function of time

For the suggested distance the shadow has a height of

y = 114.4 / (22-13)

y = 67.6 feet

7 0

3 years ago

If opposite poles repel each other, why does the north end of a compass point to the north pole?

lina2011 [118]

Ratios are fractions

6 0

3 years ago