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dexar [7]
3 years ago
12

Why does a solid change to liquid when heat is added?

Chemistry
2 answers:
sveticcg [70]3 years ago
8 0

Answer:

It is because the space between particles decreases but also loses energy at the same time.

Explanation:

Free_Kalibri [48]3 years ago
3 0
The answer is C, the molecules and atoms start vibrating causing them to space out when fast enough.
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What is poly mineralic rock
Art [367]
A rock with different rocks combined to make it

Like quartzite is made up of quartz but granite is made of quartz , feildspar and mica

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7 0
3 years ago
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At a certain temperature Kc = 9.0 for the equilibrium 24() ⇔ 22(). What is
Iteru [2.4K]

Answer:

.

Explanation:

.

5 0
4 years ago
What is Li+1 atomic mass
zvonat [6]

Answer:

7.941

Explanation:

You can look at a picture of the periodic table.To calculate the atomic mass of a single atom of an element, add up the mass of protons and neutrons. Example: Find the atomic mass of an isotope of carbon that has 7 neutrons. You can see from the periodic table that carbon has an atomic number of 6, which is its number of protons.

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3 0
4 years ago
Consider the combustion of octane (C8H18)
sesenic [268]
The balanced equation for the above reaction is as follows;
2C₈H₁₈ + 25O₂ --->  16CO₂  + 18H₂O
stoichiometry of octane to CO₂ is 2:16
number of C₈H₁₈ moles reacted - 191.6 g / 114 g/mol = 1.68 mol
when 2 mol of octane reacts it forms 16 mol of CO₂
therefore when 1.68 mol of octane reacts - it forms 16/2 x 1.68 = 13.45 mol of CO₂
number of CO₂ moles formed - 13.45 mol
therefore mass of CO₂ formed - 13.45 mol x 44 g/mol = 591.8 g
 mass of CO₂ formed is 591.8 g
3 0
3 years ago
The half-life of cesium-137 is 30 years. Suppose we have a 200-mg sample. (a) Find the mass that remains after t years.
scZoUnD [109]

Given:

Half life(t^ 1/2) :30 years

A0( initial mass of the substance): 200 mg.

Now we know that

A= A0/ [2 ^ (t/√t)]

Where A is the mass that remains after t years.

A0 is the initial mass

t is the time

t^1/2 is the half life

Substituting the given values in the above equation we get

A= [200/ 2^(t/30) ] mg


Thus the mass remaining after t years is [200/ 2^(t/30) ] mg

5 0
4 years ago
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