This is a two part question: What is the force of friction acting on a 100 kg steel slab at rest on a steel floor?
1 answer:
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This question can be solved by using the equations of motion.
a) The initial speed of the arrow is was "9.81 m/s".
b) It took the arrow "1.13 s" to reach a height of 17.5 m.
a)
We will use the second equation of motion to find out the initial speed of the arrow.
where,
vi = initial speed = ?
h = height = 35 m
t = time interval = 2 s
g = acceleration due to gravity = 9.81 m/s²
Therefore,
<u>vi = 9.81 m/s</u>
b)
To find the time taken by the arrow to reach 17.5 m, we will use the second equation of motion again.
where,
g = acceleration due to gravity = 9.81 m/s²
h = height = 17.5 m
vi = initial speed = 9.81 m/s
t = time = ?
Therefore,
solving this quadratic equation using the quadratic formula, we get:
t = -3.13 s (OR) t = 1.13 s
Since time can not have a negative value.
Therefore,
<u>t = 1.13 s</u>
Learn more about equations of motion here:
brainly.com/question/20594939?referrer=searchResults
The attached picture shows the equations of motion in the horizontal and vertical directions.
Newton's second law and graphical analysis allow us to find the correct answer for the measure of the constant b is:
D) Stack several filters to change the mass measure the acceleration of the system.
Newton's second law establishes a relationship between the net force, the mass and the acceleration of the bodies.
∑ F = m a
Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.
They indicate that the drag force on the filters is
F = - b v
Where b is a positive constant that depends on the shape and area of the filter and v is the speed of the filter.
Let's write Newton's second law.
W - fr = ma
W -bv = ma
In the experiment the students indicate that they can measure the position, velocity and acceleration of the body.
Based on the above, if we place several filter weights and measure their speed and acceleration in each case, we can make a graph of velocity versus acceleration, we can take the value of the constant b from the slope.
Let's analyze the different answers:
A) False. The constant b depends on the shape of the filter therefore it must be kept constant.
B) False. The constant depends on the area, so it must be kept constant.
C) May be. In this case, since we have the terminal velocity, the acceleration is zero, Newton's second law remains.
B v - W = 0
b =
The problem with the method is the difficulty of measuring the compression terminal velocity.
D) True. According to the discussion of the velocity versus acceleration. graph, the constant b is equal to the slope of the graph.
E) May be. The problem with this method is finding a reliable value for the terminal velocity.
In conclusion, using Newton's second law and graphical analysis we can find the correct answer for the measure of the constant b is:
D) Stack several filters to change the mass measure the acceleration of the system.
Learn more here: brainly.com/question/2441565
Answer:
a) a = 3.72 m / s², b) a = -18.75 m / s²
Explanation:
a) Let's use kinematics to find the acceleration before the collision
v = v₀ + at
as part of rest the v₀ = 0
a = v / t
Let's reduce the magnitudes to the SI system
v = 115 km / h (1000 m / 1km) (1h / 3600s)
v = 31.94 m / s
v₂ = 60 km / h = 16.66 m / s
l
et's calculate
a = 31.94 / 8.58
a = 3.72 m / s²
b) For the operational average during the collision let's use the relationship between momentum and momentum
I = Δp
F Δt = m v_f - m v₀
F =
F = m [16.66 - 31.94] / 0.815
F = m (-18.75)
Having the force let's use Newton's second law
F = m a
-18.75 m = m a
a = -18.75 m / s²