A = 
= ω²r
This is a two part question: What is the force of friction acting on a 100 kg steel slab at rest on a steel floor?
1 answer:
You might be interested in
Answer :
(a) The acceleration of the car is,
(b) The distance covered by the car is, 150 m
Explanation :
By the 1st equation of motion,
...........(1)
where,
v = final velocity = 5 m/s
u = initial velocity = 25 m/s
t = time = 10 s
a = acceleration of the car = ?
Now put all the given values in the above equation 1, we get:
The acceleration of the car is,
By the 2nd equation of motion,
...........(2)
where,
s = distance covered by the car = ?
u = initial velocity = 25 m/s
t = time = 10 s
a = acceleration of the car =
Now put all the given values in the above equation 2, we get:
By solving the term, we get:
The distance covered by the car is, 150 m