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Xelga [282]
3 years ago
9

Three piezometers located 1000 m apart bottom in the same horizontal aquifer. Piezometer A is due south of piezometer B and piez

ometer C is to the east of the line AB. The surface elevations of A, B, and C are 95, 110, and 135 m, respectively. The depth to water in A is 5 m, in B is 30 m, and in C is 35 m. Determine the direction of ground-water flow through the triangle ABC and calculate the hydraulic gradient.

Engineering
1 answer:
leva [86]3 years ago
3 0

Answer:

Hydraulic gradient=0.0173

Explanation:

The hydraulic head at the points A, B and C will be as follows

A=95-5=90 m

B=110-30=80 m

C=135-35= 100 m

By drawing the equipotential lines, the direction of ground water can be seen as in the triangle

The length of flow will be

L=\sqrt {1000^{2}-500^{2}}\approx 866.025 m

The hydraulic gradient will be given by

i=\frac {\triangle h}{L}=\frac {95-80}{866.025}\approx 0.0173

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The diameter of an extruder barrel = 85 mm and its length = 2.00 m. The screw rotates at 55 rev/min, its channel depth = 8.0 mm,
babunello [35]

Answer:

Qx = 9.109.10^5 \times 10^{-6} m³/s  

Explanation:

given data

diameter = 85 mm

length = 2 m

depth = 9mm

N = 60 rev/min

pressure p = 11 × 10^6 Pa

viscosity n = 100 Pas

angle = 18°

so  Qd will be

Qd = 0.5 × π² ×D²×dc × sinA × cosA   ..............1

put here value and we get

Qd = 0.5 × π² × ( 85 \times 10^{-3} )²× 9  \times 10^{-3}  × sin18 × cos18

Qd = 94.305 × 10^{-6} m³/s

and

Qb = p × π × D × dc³ × sin²A ÷  12  × n × L    ............2

Qb = 11 × 10^{6} × π × 85 \times 10^{-3}  × ( 9  \times 10^{-3} )³ × sin²18 ÷  12  × 100 × 2

Qb = 85.2 × 10^{-6} m³/s

so here

volume flow rate Qx = Qd - Qb   ..............3

Qx =  94.305 × 10^{-6}  - 85.2 × 10^{-6}  

Qx = 9.109.10^5 \times 10^{-6} m³/s  

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Answer:

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Explanation:

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