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Dimas [21]
2 years ago
12

Please tell me why the answer is zero

Physics
2 answers:
Oduvanchick [21]2 years ago
5 0

This question is checking to see whether you understand the meaning
of "displacement".

Displacement is a vector: 

-- Its magnitude (size) is the distance between the start-point and
the end-point, no matter what route might have been followed along
the way.

-- Its direction is the direction from the start-point to the end-point.

Talking about the Earth's orbit around the sun, we can forget about
the direction of the displacement, and just talk about its magnitude
(size).

If we pretend that the sun is not moving and dragging the whole
solar system along with it, then what do we see the Earth doing
in one year ? 
We mark the place where the Earth is at the stroke of midnight
on New Year's Eve.  Then we watch it as it swings around through
this gigantic orbit, all the way around the sun, and in a year, it's back
to the same point that we marked ! 

So what's the magnitude of the displacement in exactly one year ?
It's the distance between the start-point and the end-point.  But the
Earth came back to the same place it started from, so there's no
separation at all between the start-point and the end-point. 
The Earth covered a huge distance in that year, but the displacement
is zero.

alisha [4.7K]2 years ago
3 0
Hi

Displacement refers to the direct distance between the end and start positions. So, if I were to walk 10m north and then 10m south, the distance covered by me would be 20m but the displacement would be 0m since I'm back where I started from. So, the answer would be zero because the earth would be back at the same spot as it was a year ago in that time.
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A 57 kg boy and a 41 kg girl use an elastic rope while engaged in a tug-of-war on a frictionless icy surface. If the acceleratio
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Answer:

Acceleration of the boy a₁:

a_{1} = 1.87 \frac{m}{s^{2} }

Explanation:

Conceptual analysis

We apply Newton's second law to the boy and the girl:

F = m*a (Formula 1)

F : Force in Newtons (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Nomenclature

m₁ : boy mass

m₂ :  girl mass

a₁ : boy acceleration

a₂ :  girl acceleration

F₁ : boy acceleration

F₂ :  girl acceleration

Known data

m₁ =  57 kg

m₂ =  41  kg

a₂ = 2.6 m/s²

Problem development

We apply to Newton's third law of action and reaction, then:

F₁ = F₂ , We apply the formula (1):

m₁*a₁ = m₂*a₂

a_{1} = \frac{m_{2}* a_{2} }{m_{1} }

a_{1} = \frac{41* 2.6 }{ 57 }

a_{1} = 1.87 \frac{m}{s^{2} }

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A billiard ball of mass m hits another one of the same mass. The first ball moves off at 30 degrees. For an elastic collision wh
sleet_krkn [62]

Answer:

v₁ = u₁/2√3 ≈ 0.866u₁

v₂ = u₁/2      = 0.5u₁

θ = 60°

Explanation:

let u₁ be the initial velocity of the first ball

let v₁ be the final velocity of the first ball

let v₂ be the final velocity of the second ball

For elastic collisions, the angle between the departing masses is 90°

assume the first ball initially moves along the x axis in the positive direction

conservation of momentum

In the y direction, initial momentum is zero

After the collision

mv₁sin30 = mv₂sin60

½v₁ = ½√(3)v₂

v₁ = √(3)v₂

in the x direction,

mu₁ = mv₁cos30 + mv₂cos-60

u₁ = v₁cos30 + v₂cos60

u₁ = (√(3)v₂)½√(3) + ½v₂

u₁ = 2v₂

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