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azamat
3 years ago
6

Which of the following is a testable hypothesis?

Chemistry
2 answers:
Inga [223]3 years ago
8 0
I'm thinking it would be letter B!
Sonja [21]3 years ago
6 0
The answer would be B because you can go and find evidence and facts to conduct an investigation on that.
You might be interested in
How many moles are in 3.45g of KCI ?
artcher [175]
<h3>Answer:</h3>

0.0463 mol KCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.45 g KCl

<u>Step 2: Identify Conversions</u>

Molar Mass of K - 39.10 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of KCl - 39.10 + 35.45 = 74.55 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.45 \ g \ KCl(\frac{1 \ mol \ KCl}{74.55 \ g \ KCl})
  2. Multiply/Divide:                \displaystyle 0.046278 \ mol \ KCl

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.046278 mol KCl ≈ 0.0463 mol KCl

8 0
3 years ago
Give the word equation for the neutralization reaction of an acid and a base.
Grace [21]

Answer:Acid+Base--> salt+water

Explanation:the reaction between acids and bases is called neutralization and will always produce salt and water

7 0
4 years ago
The speed of sound in water is 350m/s. If a sound wave has the frequency of 50Hz.
Elena-2011 [213]

Answer:

Explanation

Let, Wavelength = W,

Given, frequency (f) = 50 Hz, wave velocity (V) = 342 m/s

We know, V = f × W

=> 342 = 50 × W

=> W = 342/50 metre

=> W = 6.84 metre

3 0
3 years ago
To what final concentration of NH3 must a solution be adjusted to just dissolve 0.060 mol of NiC2O4 (Ksp = 4×10−10) in 1.0 L of
ololo11 [35]
Given:
0.060 mol of NiC2O4
Ksp = 4 x 10⁻¹⁰
1.0 L of solution
Kf of Ni(NH3)6 2⁺ = 1.2 x 10⁹
<span>NiC2O4 + 6NH3 ⇋ Ni(NH3)6 2+ + 2O4 2- </span>
<span>NiC2O4 ⇋ Ni 2+ + C2O4 2- ...Ksp </span>
<span>Ni2+ + 6NH3 ⇋ Ni(NH3)6 2+...Kf </span>

Ksp * Kf = (4 x 10⁻¹⁰) * (1.2 x 10⁹) = 0.48

K = 0.48 = [Ni(NH3)6 2+][C2O4 2-] / [NH3]⁶<span> 
</span>0.48 = (0.060)² / [NH3]⁶<span> ... (dissolved C2O4 2- = 0.060M) 
</span><span>[NH3]</span>⁶<span> = (0.060)</span>²<span> / 0.48 = </span>0.0036 / 0.48 = 0.0075
NH3 = ⁶√0.0075 

NH3 = 0.44 M

3 0
3 years ago
Compared to the normal freezing point and boiling point of water, a 1-molar solution of sugar in water will have a
marysya [2.9K]

Answer :

  • Boiling point of the sugar solution will be higher than that of water's boling point.
  • Freezing point of the sugar solution will be lower than that of water's freezing point.

Explanation:

  • Boiling point of a liquid is defined as temperature at which vapor pressure of liquid becomes equal to the atmospheric pressure.

Boiling point of solution is always higher than that of the pure solvent

Vapor pressure increases with increase in temperature which means sugar solution will be heated more to make vapor pressure equal to atmospheric pressure.

  • Freezing point is defined as temperature at which solid and liquid phase are at equilibrium or temperature at which vapor pressure of liquid becomes equal to the vapor pressure in its solid phase.

Freezing point of solution is always lower than that of the pure solvent.

Lower the temperature, lower will be the vapor pressure which sugar solution solution will get freeze at lower temperature than that of the water.

6 0
3 years ago
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