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3 years ago

One unethical decision won't cause any harm.( true) or (false)

Engineering

2 answers:

konstantin123 [22]3 years ago

7 0

Answer:

true

Explanation:

BartSMP [9]3 years ago

3 0

Answer:

false

Explanation:

any one decision and mess up the entire project and lead to more things

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Allisa [31]

What do u need? Rusbaisuwvwbs

5 0

3 years ago

Read 2 more answers

On the first statistics exam, the coefficient of determination between the hours studied and the grade earned was 80%. The stand

True [87]

Answer:

$\left[\begin{array}{ccccc}&DF&SS&MS&F\\Regression&1&7200&7200&72\\Error&18&1800&100\\total&19&900\end{array}\right]$

Explanation:

Sample size, n=20

Degrees of freedom is 1

Number of degrees of freedom for error is n-2 hence 20-2=18

Total number of degrees of freedom is 18+1=19

Standard error estimate is $s_{y-x}=\sqrt {\frac {SSE}{n-2}}$

Here, $SSE=(n-2)s_{y-x}^{2}=(20-2)(10)^{2}=1800$

Coefficient of determination $r^{2}=\frac {SSE}{SS total}$

Here, $SSR=r^{2}(SSR+SSE)$

$SSR=\frac {r^{2}}{1-r^{2}} SSE=\frac {0.8}{1-0.8}(1800)=7200$

The total sum of squares is

SS total=SSR+SSE=7200+1800=9000

MSR=SSR=7200

$MSE=\frac {SSE}{n-2}=\frac {1800}{20-2}=100$

F value is given by

$F=\frac {MSR}{MSE}=\frac {7200}{100}=100$

The ANOVA table is then

$\left[\begin{array}{ccccc}&DF&SS&MS&F\\Regression&1&7200&7200&72\\Error&18&1800&100\\total&19&900\end{array}\right]$

4 0

4 years ago

A paper clip is made of wire 0.75 mm in diameter. If the original material from which the wire is made is a rod 25 mm in diamete

Bas_tet [7]

Answer:

True strain = 3.7704

Explanation:

Strain is the measure an object that is stretched or deformed. This occurs when a force is applied to an object. Strain deals mostly with the change in length of the object. Strain = Δ L /L = Change in Length over the original Length:

Volume Constancy :

ΔL/L0=A0/ΔA=(D0/ ΔD)=(25mm/0.75mm)^2

ΔL/L0=44.4

Engineering strain:

Engineering strain =ΔL-L0/L0=ΔL/L0-1

Engineering strain =44.4-1=43.4

True strain, ε=In(ΔL/L0)=In(43.4)=3.7704

Note that strain has no unit, so the True strain = 3.7704

8 0

4 years ago

An overhead 25m-long, uninsulated industrial steam pipe of 100-mm diameter, is routed through a building whose walls and air are

wariber [46]

Answer:

1) q=18414.93 W

2) C=12920$

Explanation:

Given data:

pipe length L=25m

pipe diameter D=100mm =0.1 m

air temperature $T_{s1}$ = $T_{\infty1} }$ =25 °C.....= 298.15k

pipe surface temp $T_{s2}$ =150 °C.....=423.15k

surface emissivity e= 0.8

boiler efficiency η=0.90

natural gas price Cg=$0.02 per MJ

1) Total heat loss and radiation heat loss combined

q= $q_{conv} +q_{rad}$

q= $A[h(T_{s2}-T_{s1})+e$ б( $T_{s2}$ ^4- $T_{s1}$ ^4)]....... (1)

б=5.67×10^-8 W/m^2K^4 (boltzmann constant)

area A =L.Dπ=25×0.1π=7.85 m^2

putting all these values in eq (1)

q=18414.93 W

2) suppose boiler is operating non stop annual energy loss will be

E=q.t

=18414.93.3600.24.365

=5.81×10^11 J

to find furnace energy consumption

Ef =E/η

=6.46×10^5 MJ

annual cost

C=Cg. Ef

=12920$

8 0

3 years ago

A copper block receives heat from two different sources: 5 kW from a source at 1500 K and 3 kW from a source at 1000 K. It loses

LUCKY_DIMON [66]

Answer:

a) Zero

b) the rate of entropy generation in the system's universe = ds/dt = 0.2603 KW/K

Explanation:

a) In steady state

Net rate of Heat transfer = net rate of heat gain - net rate of heat lost

Hence, the rate of heat transfer = 0

b) In steady state, entropy generated

ds/dt = - [ Qgain/Th1 + Qgain/Th2 - Qlost/300 K]

Substituting the given values, we get –

ds/dt = -[5/1500 + 3/1000 – (5+3)/300]

ds/dt = - [0.0033 + 0.003 -0.2666]

ds/dt = 0.2603 KW/K

6 0

4 years ago