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slega [8]
3 years ago
8

Hey Google please how what types of elements are crop in P block right with example​

Chemistry
2 answers:
Arte-miy333 [17]3 years ago
3 0

Explanation:

you can google it but if you can't get I will ask my teacher and write the full question

enyata [817]3 years ago
3 0

Answer:

The elements of groups 13, 14, 15, 16, 17, 18 are called p block elements.examples: boron (B), aluminium (Al), gallium (Ga), indium (In), thallium (Tl),and so on

Explanation:

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How many molecules are there in 1024 grams of Na2SO4?
tino4ka555 [31]

Answer:

1.91 x 450 molecules

Explanation:

4 0
3 years ago
Anybody wanna do a zoom
Ksivusya [100]
For what exactly ? just for fun or for educational purposes?
8 0
2 years ago
A student mixes four reagents together, thinking that the solutions will neutralize each other. The solutions mixed together are
vaieri [72.5K]

Answer: Resulting solution will not be neutral because the moles of OH^-ions is greater. The remaining concentration of [OH^-]ions =0.0058 M.

Explanation:

Given,

[HCl]=0.100 M

[HNO_3] = 0.200 M

[Ca(OH)_2] =0.0100 M

[RbOH] =0.100 M

Few steps are involved:

Step 1: Calculating the total moles of H^+ ion from both the acids

moles of H^+ in HCl

HCl\rightarrow {H^+}+Cl^-

if 1 L of HClsolution =0.100 moles of HCl

then 0.05L of HCl solution= 0.05 \times0.1 moles= 0.005 moles    (1L=1000mL)

moles of H^+ in HCl = 0.005 moles

Similarliy

moles of H^+ in HNO_3

HNO_3\rightarrow H^++NO_3^-}

If 1L of HNO_3 solution= 0.200 moles

Then 0.1L of HNO_3 solution= 0.1 \times 0.200 moles= 0.02 moles

moles of H^+ in HNO_3 =0.02 moles

so, Total moles of H^+ ions  = 0.005+0.02= 0.025 moles     .....(1)

Step 2: Calculating the total moles of [OH^-] ion from both the bases

Moles of OH^-\text{ in }Ca(OH)_2

Ca(OH)_2\rightarrow Ca^2{+}+2OH^-

1 L of Ca(OH)_2= 0.0100 moles

Then in 0.5 L Ca(OH)_2 solution = 0.5 \times0.0100 moles = 0.005 moles

Ca(OH)_2 produces two moles of OH^- ions

moles of OH^- = 0.005 \times 2= 0.01 moles

Moles of OH^- in RbOH

RbOH\rightarrow Rb^++OH^-

1 L of RbOH= 0.100 moles

then 0.2 [RbOH] solution= 0.2 \times 0.100 moles = 0.02 moles

Moles of OH^- = 0.02 moles

so,Total moles of OH^- ions = 0.01 + 0.02=0.030 moles      ....(2)

Step 3: Comparing the moles of both H^+\text{ and }OH^- ions

One mole of H^+ ions will combine with one mole of OH^- ions, so

Total moles of H^+ ions  = 0.005+0.02= 0.025 moles....(1)

Total moles of OH^- ions = 0.01 + 0.02=0.030 moles.....(2)

For a solution to be neutral, we have

Total moles of H^+ ions = total moles of OH^- ions

0.025 moles H^+ will neutralize the 0.025 moles of OH^-

Moles of OH^- ions is in excess        (from 1 and 2)

The remaining moles of OH^- will be = 0.030 - 0.025 = 0.005 moles

So,The resulting solution will not be neutral.

Remaining Concentration of OH^- ions = \frac{\text{Moles remaining}}{\text{Total volume}}

[OH^-]=\frac{0.005}{0.85}=0.0058M

6 0
3 years ago
Which model would represent asexual reproduction? explain you reasoning
matrenka [14]

Answer:

Answer)   The first box represent the budding type of asexual reproduction . In budding due to the cell divison at the particular place in the organism , new  individual will produced.

Second picture represent the budding in hydra. Budding is also a asexual reproduction.

Third type of asexual reproduction is found in plants  it is vegetative reproduction.

Fourth is Binary fission . This is also a type of asexual reproduction, in which nucleus dicied into two new daughter cell via mitosis.Explanation:

8 0
3 years ago
Write the molecular formula for acetaldehyde? enter the elements in the order cho.
mafiozo [28]

The chemical formula which shows the number of atoms for every element present in the molecule is said to be molecular formula.

Acetaldehyde is an organic compound having -CHO functional group. It is also called as ethanal.

Now, ethanal consist of one carbon atom which is linked with  three hydrogen atoms and it is linked with one functional group i.e. aldehyde.

Thus, molecular formula of acetaldehyde is CH_{3}CHO.

5 0
3 years ago
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