0.53 x 200ml = 106 ml of the pH 9.0 buffer + 94 ml of the pH 10 buffer gives the desired solution
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Not sure about the first one , but the second one is ONE
0.0036g of NH4+ x 1mol of NH4+/18.04g of NH4+ x 6.02*10^23 electrons of NH4+/1mol of NH4+
= 1.20 x 10^20 electrons of NH4+
Answer:
i want to help but i d k. the answer :( sorry i couldnt help
Explanation: