Combustion of Fossil Fuels
Explanation:
The combustion of fossil fuels is a major contributor to unbalancing of the carbon cycle which causes more carbon dioxide to be released into the air than can be naturally processed.
Combustion of fossil fuel is an anthropogenic source of carbon dioxide emission. This chemical process is used to power internal combustion engines and industrial activities. The by product is usually carbon dioxide.
Plants that use carbon dioxide for their life processes cannot completely absorb all of this anthropogenic emission.
Naturally, animal respiration and decomposition provides enough carbon dioxide for use during photosynthesis. Combustion of fossil fuels tips this balance.
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It is very cold there 90 degrees celsius so dress very warm!
Answer:
When considering phase changes, the closer molecules are to one another, the stronger the intermolecular forces. Good! For any given substance, intermolecular forces will be greatest in the solid state and weakest in the gas state.
In the case of melting, added energy is used to break the bonds between the molecules. ... If heat is coming into a substance during a phase change, then this energy is used to break the bonds between the molecules of the substance. The example we will use here is ice melting into water.
<span>Light
from the sun provides energy for life’s processes. It enables the primary
producers (photosynthetic organisms) such as phytoplankton
and plants to produce organic molecules from abiotic factors. This energy is passed up as primary and secondary
consumers consume these producers and this cycle
continues up the foods chain/web. </span>
Answer:
About 0.1738 liters
Explanation:
Using the formula PV=nRT, where p represents pressure in atmospheres, v represents volume in liters, n represents the number of moles of ideal gas, R represents the ideal gas constant, and T represents the temperature in kelvin, you can solve this problem. But first, you need to convert to the proper units. 215ml=0.215L, 86.4kPa is about 0.8527 atmospheres, and 15C is 288K. Plugging this into the equation, you get:

Now that you know the number of moles of gas, you can plug back into the equation with STP conditions:

Hope this helps!