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sp2606 [1]
3 years ago
14

C6H14 reacts with oxygen gas and produces 2 products reaction type of chemical equation​

Chemistry
2 answers:
stepan [7]3 years ago
7 0

Answer: reaction type is combustion

Explanation:

C6H14 + 19/2O2 ==> 6CO2 + 7H2O

BaLLatris [955]3 years ago
5 0

Answer: Reaction type: Combustion reaction

2 C6H14 + 19 O2 => 12 CO2 + 14 H2O

Explanation: The number of atoms on both sides in the reactant and product are equal.

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Which of the following was a major contribution to chemistry by antoine lavoisier
Artemon [7]
 he showed that oxygen is required to burn.
8 0
3 years ago
A 3.0 g sample of a gas occupies a volume of 1.00L at 100C and 740 torr pressure. The molecular weight of the
SOVA2 [1]

Answer:

94.2 g/mol

Explanation:

Ideal Gases Law can useful to solve this

P . V = n . R . T

We need to make some conversions

740 Torr . 1 atm/ 760 Torr = 0.974 atm

100°C + 273 = 373K

Let's replace the values

0.974 atm . 1 L = n . 0.082 L.atm/ mol.K . 373K

n will determine the number of moles

(0.974 atm . 1 L) / (0.082 L.atm/ mol.K . 373K)

n = 0.032 moles

This amount is the weigh for 3 g of gas. How many grams does 1 mol weighs?

Molecular weight → g/mol → 3 g/0.032 moles = 94.2 g/mol

3 0
3 years ago
Consider the following isotopic abundance data for argon (Ar) and silicon (Si):
pshichka [43]

Answer:

Explanation:

Molar mass of Argon

= 35.96755 x .00337 + 37.96272 x .00063 + 39.96240 x .99600

= .12121 + .0239165 + 39.80255

= 39.95

Molar mass of silicon

27.97693 x .9223 + 28.97649 x .0467 + 29.97376 x .0310

= 25.803 + 1.35320 + .929

= 28.08

b )

No of atoms of Si  in 78.2 g = 78.2 x 6.02 x 10²³ / 28.08

= 16.76 x 10²³ .

c )

42 Ar / 40 Ar = 1.05006

42 Ar / 39.95 = 1.05006

42Ar = 41.95

2 )

C₁₆H₁₅F₂N₃O₄S

Mol weight = 16 x 12 + 1 x 15 + 2 x 19 + 3 x 14 + 4 x 16 + 32

= 192 + 15 + 38 + 42 + 64+ 32

= 383

No of molecules = .078 x 6.02 x 10²³ / 383

= 1.226 x 10²⁰ molecules .

7 0
3 years ago
Quis critérios foram usadps por dobereiner em sua tentava de organiza os elementos químicos?
anyanavicka [17]

Döbereiner grouped the known elements into <em>triads</em> (sets of three) so that

• The <em>atomic mass of the middle element</em> was approximately the average    of the other two

• The <em>chemical properties of the middle element</em> were between those of the other two

• The <em>physical properties of the middle element</em> were between those of the other two

One example of a triad is Li – Na – K.

(a) Atomic mass of Na = 23.0 u

       Average atomic mass of Li and K = (6.9 u + 39.1 u)/2 = 46.0 u/2 = 23.0 u

(b) Li reacts slowly with water. Na reacts rapidly. Potassium reacts violently.

(c) Melting point of Na = 371 °C.

       Average melting point of Li and K = (454 °C + 330 °C)/2 = 784 °C/2

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8 0
3 years ago
why are plasmas of great interest to scientists or manufacturers. descride 2 current uses of plasmas and describe 1 way scientis
Helga [31]

<u>Answer:</u>

<u>Plasmas of great interest to scientists or manufacturers as</u>

  • Plasma is electrically charged gases that contain considerable charged particles that can change the behavior of the substance.

<u>Current uses of plasmas:</u>

  • First, it is used to make semiconductors for different types of electronic equipment
  • Secondly, they're used in making transmitters for high-temperature films.

<u>Way scientists and engineers hope to use plasmas in the future:</u>

  • The scientists are hoping to use plasma in the future to get rid of all hazardous wastes through a process called plasma gasification.

6 0
3 years ago
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