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sweet [91]
4 years ago
9

How many li are in 2.5 moles of li​

Chemistry
1 answer:
NARA [144]4 years ago
8 0

Answer:

15.06 × 10²³ atoms of Li

Explanation:

Given data:

Number of moles of Li = 2.5 mol

Number of toms of Li = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 2.5 mol of Li:

1 mole of lithium = 6.022 × 10²³ atoms of Li

2.5 mol × 6.022 × 10²³ atoms of Li / 1 mol

15.06 × 10²³ atoms of Li

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N2+3H2—> 2NH3 What volume of NH3 at STP is produced if 25.0g of N2 is reacted with an excess of H2 ?
Butoxors [25]

Answer:

The answer to your question is 40 L of NH₃

Explanation:

Data

Volume of NH₃ = x

mass of N₂ = 25 g

mass of H₂ = excess

Balanced chemical reaction

                     N₂  +  3H₂   ⇒  2NH₃

Process

1.- Find the molar mass of N₂ and NH₃

N₂ = 14 x 2 = 28g

2NH₃ = 2[ 14 + 3] = 34 g

2.- Write a proportion to solve this problem

                    28 g of N₂ --------------- 34 g of NH₃

                     25 g of N₂ -------------   x

                     x = (25 x 34)/28

                     x = 30.36 g of NH₃

3.- Calculate the volume of NH₃

                     17 g of NH₃ -------------- 22.4 L

                     30.36 g of NH₃ --------  x

                     x = (30.36 x 22.4) / 17

                     x = 40 L

6 0
3 years ago
Given the following reaction: 2N2O5=2N2O4+O2, if the rate of oxygen production is 0.15M/min, determine:
astraxan [27]

Answer:

a. r_{N_2O_5}=-0.075M/min

b. r_{N_2O_4}=0.075M/min

Explanation:

Hello.

In this case, according to the balanced chemical reaction, we can write the law of rate proportions:

\frac{r_{N_2O_5}}{-2} =\frac{r_{N_2O_4}}{2} =\frac{r_{O_2}}{1}

Thus, we proceed as follows:

a. Since the rate of oxygen production is 0.15 M/min, we can make the following setup:

\frac{r_{N_2O_5}}{-2}  =\frac{r_{O_2}}{1}\\\\r_{N_2O_5}=\frac{r_{O_2}}{-2}  =\frac{0.15M/min}{-2}\\\\ r_{N_2O_5}=-0.075M/min

b. Since the rate of oxygen production is 0.15 M/min, we can make the following setup:

\frac{r_{N_2O_4}}{2}  =\frac{r_{O_2}}{1}\\\\r_{N_2O_4}=\frac{r_{O_2}}{2}  =\frac{0.15M/min}{2}\\\\ r_{N_2O_4}=0.075M/min

Best regards!

8 0
3 years ago
Which letter? Thanks in advance!
Mashcka [7]

Answer: b

Explanation:

7 0
3 years ago
NEED HELP AND WILL RATE BRAINLIEST!!!!<br> I need help with question 3
IrinaK [193]
I think the answer is B or the 2nd one, hope this helped c:
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3 years ago
I neeed help with science can someone give me a good explanation please.
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Answer:

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