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Elena-2011 [213]
4 years ago
13

Which toe of energy change takes place as a car burns fuel to race down a track

Chemistry
1 answer:
Cerrena [4.2K]4 years ago
7 0
Toe? Do you mean which toe like feet or a different toe



Explanation:
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pychu [463]

Answer:

Pareto diagram or bar graph

Explanation:

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3 years ago
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What is the wavelength (in meters) of an electromagnetic wave whose frequency is 2.63 × 1012 s−1?
aleksklad [387]
To find the wavelength of an  electromagnetic wave for the given frequency can be determined by using the formulaSpeed=Wavelength x FrequencyWavelength=Speed/FrequencyGenerally Speed of the electromagnetic wave is 3x10^8 m/sBy substituting the values Wavelength=3x10^8 m/s / 2.63x10^12 s^-1Wavelength=1.14 x 10^-4 metres
4 0
3 years ago
If a pork roast must absorb kJ to fully cook, and if only 10% of the heat produced by the barbecue is actually absorbed by the r
kolezko [41]

Answer:

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

Explanation:

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g),\Delta H_{rxn}=-2044 kJ/mol (assuming)

Energy absorbed by pork,E = 1.6\times 10^3 kJ (assuming)

Total energy produced by barbecue = Q

Percentage of energy absorbed by pork = 10%

10\%=\frac{E}{Q}\times 100

Q=\frac{E}{10}\times 100=\frac{1.6\times 10^3 kJ}{10}\times 100=1.6\times 10^4 kJ

Since, it is a energy produced in order to indicate the direction of heat produced we will use negative sign.

Q = -1.6\times 10^4 kJ

Moles of propane burnt to produce Q energy =n

n\times \Delta H_{rxn}=Q

n=\frac{Q}{\Delta H_{rxn}}=\frac{-1.6\times 10^4 kJ}{-2044 kJ/mol}=7.83 mol

According to reaction , 1 mol of propane gives 3 moles of carbon dioxide. then 7.83 moles of will give:

\frac{1}{3}\times 7.83 mol=23.49 mol carbon dioxide gas.

Mass of 23.49 moles of carbon dioxide gas:

23.49 mol × 44 g/mol =1,033.56 g

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

8 0
3 years ago
How is a suspension different from a colloid?
Mashcka [7]

Answer:

Explanation:

Colloidal:

  • Colloid consist of the particles having size between 1 - 1000 nm i.e, 0.001- 1μm.  
  • The particles in colloid can not be seen through naked eye.
  • It is homogeneous.
  • We can not separate the colloidal through the filtration. The pore size of filter paper is 2μm. However it can be separated through the ultra filtration. In ultra filtration the pore size is reduced by soaking the filter paper in gelatin and then in formaldehyde. This is only in case of when solid colloidal is present, if colloid is liquid , there is no solid particles present and ultra filtration can not be used in this case.

Suspension:

  • The particle size in suspension is greater than 1000 nm.
  • These particles can seen through naked eye.
  • It is heterogeneous.  
  • The particles in suspension can be separated through the filtration.
3 0
3 years ago
 Water can dissolve other substances. Which factor best contributes to this property of water?
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6 0
3 years ago
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