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Umnica [9.8K]
3 years ago
3

Do the following density practice problems using the equation for density and the density triangle. Be sure to show all work and

to use the correct units. 1) A wooden block has a mass of 562 g and a volume of 72 cm3. What is the density?
Physics
1 answer:
lara [203]3 years ago
7 0

Answer:

\text{density} = 7.806\dfrac{\text{g}}{\text{cm}^3}

Explanation:

Density is defined as:

\text{density} = \dfrac{\text{mass}}{\text{volume}}

Given that:

mass = 562 g

volume = 72 cm^3

we can find the density:

\text{density} = \dfrac{562\text{g}}{72\text{cm}^3}

\text{density} = 7.806\dfrac{\text{g}}{\text{cm}^3}

this is our answer!

if you want to represent the density as kg/m^3. this can be easily done by converting the units.

\text{density} = 7.806\times\left(1000\,\dfrac{\text{kg}}{\text{m}^3}\right)\\\text{density} = 7806\,\dfrac{\text{kg}}{\text{m}^3}

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If Phoenix, Arizona, experiences a cool, wet day in June, does that mean the regions climate is changing?
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5 0
3 years ago
An airplane traveling at one third the speed of sound (i.e., 114 m/s) emits a sound of frequency 3.72 kHz. At what frequency doe
nlexa [21]

Answer:

f'=5.58kHz

Explanation:

This is an example of the Doppler effect, the formula is:

f'=\frac{(v+v_o)}{(v+v_s)}f

Where f is the actual frequency, f' is the observed frequency, v is the velocity of the sound waves, v_o the velocity of the observer (which is negative if the observer is moving away from the source)  and v_s the velocity of the source  (which is negative if is moving towards the observer). For this problem:

f=3.72kHz\\v=342m/s\\v_o=0m/s\\v_s=-114m/s

f'=\frac{(342+0)}{(342-114)}3.72\times10^3\\f'=\frac{342}{228}3.72\times10^3\\f'=(1.5)3.72\times10^3\\f'=5580Hz=5.58kHz

5 0
3 years ago
How the energy is transformed
ANTONII [103]

Answer:

motion energy to sound energy

Explanation:

you move your hands together, then clap then, which makes a sound. Hope that this helps you and have a great day :)

6 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST TO CORRECT ANSWER PLEASE HELP ME
koban [17]

Answer:

The total distance is 381.5 [m]

Explanation:

In order to solve this problem we must use the expressions of kinematics. The clue to solve this problem is that the motorcyclist starts from rest, i.e. its initial speed is zero.

v_{f} =v_{o} +(a*t)

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0

a = acceleration = 2 [m/s²]

t = time = 7 [s]

Vf = 0 + (2*7)

Vf = 14 [m/s]

With this velocity, we can calculate the displacement using the following expression.

v_{f} ^{2} =v_{o} ^{2} +2*a*x

where

x = distance traveled [m]

14² = 0 + (2*7*x)

x = 196/(14)

x = 14 [m]

Note: The positive sign in the equations is because the car is accelerating, it means its velocity is increasing.

The other important clue to solve this problem in the second part is that the final velocity is now the initial velocity.

We must calculate the final velocity.

v_{f}= v_{i} +(a*t)

Vf = final velocity [m/s]

Vi = initial velocity = 14 [m/s]

a = desacceleration = 4 [m/s²]

t = time = 8 [s]

Vf = 24 + (4*8)

Vf = 56 [m/s]

With this velocity, we can calculate the displacement using the following expression.

v_{f} ^{2} =v_{o} ^{2} +2*a*x

where

x = distance traveled [m]

56² = 14² + (2*4*x)

x = 2940/(8)

x = 367.5 [m]

Note: The positive sign in the equations is because the car is accelerating, it means its velocity is increasing.

Therefore the total distance is Xt = 14 + 367.5 = 381.5 [m].

4 0
3 years ago
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