Yes because we have day and night and seasons
Assuming the acceleration is constant, then we can use the derived equations for rectilinear motion. The equation is written below:
2ax = v²- v₀²
where
a is the acceleration
x is the distance
v is the final velocity
v₀ is the initial velocity
Since the car came to a stop, v = 0. Substituting the values,
2a(0.80 m) =0² - [(95 km/h)(1000 m/1 km)(1 h/3600 s)]²
Solving for a,
a = -435.23 m/s²
The sign is negative because it is decelerating.
Answer:
Explanation:
give,
Gauge pressure of car, P₁ = 30 psi
temperature,T₁ = 0° C = 0 + 273 = 273 K
Assuming temperature at the noon = 30° C
T₂ = 30 + 273 = 303 K
Pressure at this temperature, P₂ = ?
Using ideal gas equation
taking volume as in compressible V₁ = V₂
Hence, Pressure of the at 30°C is equal to 33.297 psi.
Answer:
The substrate concentration reached Vmax
Explanation:
In this scenerio, further increase in the rate of reaction was prevented because the substrate concentration hit Vmax.
Beyond the Vmax, the substrate can no longer proceed.
- The substrate is the reactant on which the enzyme works on.
- Enzymes are natural organic chemical catalysts.
- Increasing the concentration of reactants is one of the known and proven ways to speed up the rate of reaction.
- Since we have limited amount of enzymes, once they all bound to the substrate, no further increase in the substrate will have an effect on the rate.
- At the optimum reaction point, all the available substrate will bond with the enzyme.
- Beyond this, the enzymes are saturated will not further any reaction.
<h3>Answer: 500 Kilometers</h3>
Explanation:
The formula for finding distance is: speed × time
We must multiply:
200Km/h × 2.5 hours
This gives you 500 Km.
<u>Remember: the formula to work out the distance - speed x time.</u>
If the train speed is 200 km/h, it travels 200 km/h.
Now, we must multiply 200 by 2.5:
200 x 2.5 = 500
Our answer is 500 Kilometers.
