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Dahasolnce [82]
3 years ago
5

Need help with this electric physics question

Physics
1 answer:
klio [65]3 years ago
8 0

The output winding has 1/20 as many turns as the input winding has.

So the output voltage is 1/20 of the input voltage.

That's how transformers work.

Complicated, huh !

(1/20) of 240 volts = <em>12 volts</em>

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A skull believed to belong to an ancient human being has a carbon-14 decay rate of 5.4 disintegrations per minute per gram of ca
larisa86 [58]

Answer:

9.43*10^3 year

Explanation:

For this question, we ought to remember, or know that the half life of carbon 14 is 5730, and that would be vital in completing the calculation

To start with, we use the formula

t(half) = In 2/k,

if we make k the subject of formula, we have

k = in 2/t(half), now we substitute for the values

k = in 2 / 5730

k = 1.21*10^-4 yr^-1

In(A/A•) = -kt, on rearranging, we find out that

t = -1/k * In(A/A•)

The next step is to substitite the values for each into the equation, giving us

t = -1/1.21*10^-4 * In(5.4/15.3)

t = -1/1.21*10^-4 * -1.1041

t = 0.943*10^4 year

8 0
4 years ago
Each of the two coils has 320 turns. The average radius of the coil is 6 cm. The distance from the center of one coil to the ele
Temka [501]

Answer:

Magnetic field, B=2.39\times 10^{-3}\ T

Explanation:

It is given that,

Number of turns, N = 320

Radius of the coil, r = 6 cm = 0.06 m

The distance from the center of one coil to the electron beam is 3 cm, x = 3 cm = 0.03 m

Current flowing through the coils, I = 0.5 A

We need to find the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils. The magnetic field midway between the coils is given by :

B=\dfrac{\mu_oINr^2}{(x^2+r^2)^{3/2}}

B=\dfrac{4\pi \times 10^{-7}\times 0.5\times 320\times (0.06)^2}{(0.03^2+0.06^2)^{3/2}}

B = 0.00239 T

or

B=2.39\times 10^{-3}\ T

So, the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils is 2.39\times 10^{-3}\ T. Hence, this is the required solution.

7 0
4 years ago
A cyclist and his bicycle have a combined mass of 88 kg and a combined
SpyIntel [72]

Answer:D

Explanation:

Mark brainly

5 0
3 years ago
A wheel is rotating about a fixed axis with constant angular acceleration 3 rad/s². At different moments, its angular speed is -
meriva

b and e are the largest and equal in magnitude. w*2R = (2)(2)R = 4R

A and d are next. aR = (3rad/s2)R = 3R

c is zero. wR = v = 0; Angular acceleration is zero.

<h3>What is angular acceleration?</h3>
  • The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement is radians per second per second. Therefore, = d d t. Rotational acceleration is another name for angular acceleration.
  • Angular velocity divided by acceleration time can be used to define angular acceleration. (t). As an alternative, use pi times the drive speed (n) divided by the acceleration time (t) times 30. Radians per second squared (Rad/sec2) is the standard SI unit for rotational acceleration resulting from this equation.
  • To calculate angular velocity, we can use one of three formulas. The definition itself provides the first. Theta = position angle, t = time, and w = angular velocity, where w = angular velocity, theta = position angle, and t = time. Angular velocity is the rate of change of an object's position angle with respect to time.
  • The symbol for angular acceleration is, and it is measured in rad/s2, or radians per second square.

If two items are equal, show them as equal in your ranking. If a quantity is equal to zero, show that fact in your ranking:

b and e are the largest and equal in magnitude. w*2R = (2)(2)R = 4R

A and d are next. aR = (3rad/s2)R = 3R

c is zero. wR = v = 0; Angular acceleration is zero.

To learn more about angular acceleration, refer to:

brainly.com/question/20912191

#SPJ4

8 0
2 years ago
WHAT IS THE KE OF 2KG BALL AT SPEED 5M/S AT 40M TALL?
Zolol [24]
K.e=1/2mv²
K.e=1/2 2(5)²
K.e=1/2 2×25
K.e=50/2
K.e=25J
4 0
3 years ago
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