All categories

3 years ago

Need help with this electric physics question

Physics

1 answer:

klio [65]3 years ago

8 0

The output winding has 1/20 as many turns as the input winding has.

So the output voltage is 1/20 of the input voltage.

That's how transformers work.

Complicated, huh !

(1/20) of 240 volts = 12 volts

You might be interested in

A convex lens can produce a real image but not a viral image a. true b. false

serious [3.7K]

The answer is true a convex lens can produce a real image but not a viral image

5 0

3 years ago

Help me please i dont understand

alexandr402 [8]

Option A is the correct answer.

5 0

3 years ago

The distance between two charges a and b is r, and the force between them is F. What is the force between them if the distancbet

Nadusha1986 [10]

See coulomb's law. Force is inversely proportional to the distance squared. So if you multiply r by 2, the force is multiplied by (½)² = ¼.

a. F/4

7 0

3 years ago

The moon orbits the earth once every 27 days at a distance of 384400 km. The international space station orbits the earth at an

Leno4ka [110]

Answer:

ive never done this befor but i think its 36 times aroud earth a day

Explanation:

384400/400=961

961% of 27 days is 40minuets

1440/40=36

7 0

3 years ago

you are piloting a small plane and you want to reach an airport 450 km due south in 3.0 h a wind is blowing from the west 50.0 k

alex41 [277]

Answer:

You should choose airspeed 158.11 km/h at 18.4° west of south

Explanation:

The distance to the air port is 450 km due to south

You should to reach the airport in 3 hours

→ Velocity = distance ÷ time

→ Distance = 450 km , time = 3 hours

→ The velocity of your plane = 450 ÷ 3 = 150 km/h due to south

A wind is blowing from west 50 km/h

We need to know what heading and airspeed you should choose to

reach your destination

At first we must find the resultant velocity of your plane and the wind

The south and west are perpendicular, then the resultant velocity is

→ $v_{R}=\sqrt{(v_{p})^{2}+(v_{w})^{2}}$

→ $v_{p}=150$ km/h , $v_{w}=50$ km/h

→ $v_{R}=\sqrt{(150)^{2}+(50)^{2}}=158.11$ km/h

To cancel the velocity of the wind, the pilot should maintain the velocity

of the plane at 158.11 km/h

The direction of the velocity is the angle between the resultant velocity

and the vertical (south)

→ The direction of the velocity is $tan^{-1}\frac{50}{150}=18.4$ °

The direction of the velocity is 18.4° west of south

You should choose airspeed 158.11 km/h at 18.4° west of south

8 0

3 years ago