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3 years ago

Which of the following is true about acids?

Physics

2 answers:

Stells [14]3 years ago

8 0

i would say, are sour and corrode metals

GarryVolchara [31]3 years ago

5 0

Answer:

Most acids are sour, most acids corrode metals and every acid contains hydrogen.

Explanation:

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A wave passes along the surface of the water in a ripple tank. Describe the motion of a molecule on the surface as the water pas

laila [671]

Answer:

Explanation:

Water waves are generally a transverse wave which do not cause permanent displacement of molecules of the medium. Transverse waves are waves in which the direction of propagation of the wave is perpendicular to the direction of vibration of the particles of the medium.

As the wave propagates from one point to another on the surface of water transferring energy, a molecule of water on its surface vibrates upwards and downwards. Its motion is perpendicular to the direction of propagation of the wave. After the vibration, it comes back to its initial position.

8 0

3 years ago

You travel 23 meters north in 16 seconds, 5 meters south in 4 seconds, and 16 meters north in 18 seconds. Calculate your total d

dolphi86 [110]

Answer:

d: 44m

Δd:34

Explanation:

d: 23+5+16= 44m

Δd: 23-5+16= 34m

4 0

2 years ago

Some liquid is poured into a burrete so that it reads 14cm³.50 drops were run each of volume 0.1cm³ .

nika2105 [10]

Given :

Liquid is poured into a burrete so that it reads 14cm³.

50 drops were run each of volume 0.1cm³ .

To Find :

The volume of liquid in burrete after 50 drops.

Solution :

Volume of each drop, v = 0.1 cm³.

Initial volume in burrete, V = 14 cm³.

Now, volume left after droping 50 drops are :

$L = V - 50v\\\\L = 14 - 50\times 0.1 \ cm^3 \\\\L = 9 \ cm^3$

Therefore, the volume left in burrete is 9 cm³ .

5 0

3 years ago

A point charge q1 is held stationary at the origin. A second charge q2 is placed at point a, and the electric potential energy o

likoan [24]

Answer:

$U_{b}=+7.3*10^{-8}J$

Explanation:

Given data

Electric potential at point a is Ua=5.4×10⁻⁸J

q₂ moves to point b where a negative work done on it $W_{a-b}=-1.9*10^{-8}J$

Required

Electric potential energy Ub

Solution

When a particle moves from a point where the potential is Ua to a point where it is Ub the change in potential energy is equal to work done where the force exerted on the charge is conservative and work done is given by:

$W_{a-b}=U_{a}-U_{b}\\U_{b}=U_{a}-W_{a-b}$

Now substitute the given values

$U_{b}=5.4*10^{-8}J-(-1.9*10^{-8}J)\\U_{b}=+7.3*10^{-8}J$

3 0

3 years ago

Your image appears 3.0 m from a plane mirror. How far IS YOUR IMAGE IN<br> RELATION TO YOU?*

Vsevolod [243]

Answer:

Being a plane mirror the Image is formed 3 metres beyond the mirror . So total distance is 3+3 = 6metres

8 0

3 years ago

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