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3 years ago

I honestly am stuck with this question for at least 30 minutes. I NEED AN EXPERT AND HELP FAST! PLEASE HELP ME!!!

Chemistry

1 answer:

vovikov84 [41]3 years ago

5 0

Answer:

Here's what I get

Explanation:

1. Synthesis

(a) Preparation of Grignard reagent

React allyl bromide with magnesium in dry ether.

(b) Grignard reaction

Add allylmagnesium bromide to methyl phenyl ketone. Convert the alkoxide to the alcohol by treatment with aqueous ammonium chloride.

(c) 1,2-Dihydroxylation

React the alkene with tert-butyl peroxide and a catalytic amount of hydrogen peroxide. Decompose the osmate ester with aqueous sodium hydroxide.

2. Mechanism

Here are my proposed steps for the mechanisms.

(a) The 65 % Product

(i) Protonation of the secondary alcohol

(ii) Loss of the protonated OH group to form a secondary carbocation

(iii) Alkyl migration/ring expansion to form a more stable tertiary carbocation

(iv) Deprotonation to form the ketone

(b) The 25 % product

(a) Protonation of the tertiary alcohol

(ii) Loss of the protonated OH group to form a tertiary carbocation

(iii) Hydride shift to form a protonated carbonyl group

(iv) Deprotonation to form the ketone

(c) The 10 % product

(i) Electrophilic aromatic attack by the cation formed in step (b)(ii) to form a cyclopropane intermediate.

(ii) Cleavage of a cyclopropane bond to regenerate the aromatic ring and form a protonated carbonyl group

(iii) Deprotonation to form an aldehyde.

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Si se adiciona etilenglicol (compuesto no volátil) a agua destilada:

poizon [28]

Answer:

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Explanation:

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6 0

4 years ago

A saturated solution of manganese(II) hydroxide was prepared, and an acid–base titration was performed to determine its KspKsp a

trapecia [35]

Answer:

10.945 x 10^-4

Explanation:

Balanced equation:

Mn(OH)2 + 2 HCl --> MnCl2 + H2O

it takes 2 moles HCL for each mole Mn(OH)2

Next find the molarity of the Mn(OH)2 solution

= (1 mole Mn(OH)2 / 2 mole HCl) X (0.0020 mole HCl / 1000ml) X (4.86 ml)

= 4.86 x 10^-3 mole

this is now dissolved in (70 + 4.86) = 74.86 ml or 0.07486 L

thus [Mn(OH)2] = 4.86 x 10^-3 mole / 0.07486 L = 0.064921 M

Ksp = [Mn2+][OH-]^2 = 4x^3 = 4(0.064921)^3 = 10.945 x 10^-4

6 0

3 years ago

Process by which plants, algae, and many types of bacteria use sunlight, water, and carbon dioxide to make food and oxygen

Katena32 [7]

Answer: Photosynthesis

Explanation:

<em>The process of photosynthesis</em> is used to help make food for plants. The inputs are sunlight, water (H2O), and carbon dioxide (CO2). Then the outputs are glucose (C6H12O6) which is food, and oxygen (O2) is released.

I hope this helps :)

4 0

3 years ago

Determine the freezing point and boiling point of a solution that has 68.4 g of sucrose

Ymorist [56]

Answer:

Freezing T° of solution = - 3.72°C

Boiling T° of solution = 101.02°C

Explanation:

To solve this we apply colligative properties. Firstly, freezing point depression:

ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Kf = Cryoscopic constant, for water is 1.86 °C/m

m = molality (moles of solute in 1kg of solvent)

i = Ions dissolved in solution

Our solute is sucrose, an organic compound so no ions are defined. i = 1.

Let's determine the moles: 68.4 g . 1mol/ 342g = 0.2 moles

molality = 0.2 mol / 0.1kg of water = 2 m

We replace data: ΔT = 1.86°C/m . 2m . 1

Freezing T° of solution = - 3.72°C

Now, we apply elevation of boiling point: ΔT = Kb . m . i

ΔT = Boiling T° of solution - Boiling T° of pure solvent

Kf = Ebulloscopic constant, for water is 0.512 °C/m

We replace:

Boiling T° of solution - Boiling T° of pure solvent = 0.512 °C/m . 2 . 1

Boiling T° of solution = 0.512 °C/m . 2 . 1 + 100°C → 101.02°C

6 0

3 years ago

Is PO4^-3 polar, non-polar, or ionic?

Gala2k [10]

The answer is PO4^-3 is non-polar.

8 0

3 years ago

I honestly am stuck with this question for at least 30 minutes. I NEED AN EXPERT AND HELP FAST! PLEASE HELP ME!!! ​

I honestly am stuck with this question for at least 30 minutes. I NEED AN EXPERT AND HELP FAST! PLEASE HELP ME!!!