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Gala2k [10]
3 years ago
12

As a wave travels through a medium, it displaces the particle perpendicular to the motion of the wave. We can conclude that this

is a
a. longitudinal wave because of the direction that the wave travels.
b. transverse wave because of the direction in which the particles are displaced.
c. longitudinal wave because the wave is traveling through a medium displacing particles.
d. transverse because of the direction that the wave is traveling.
Physics
2 answers:
Brums [2.3K]3 years ago
5 0

The correct answer to the question is that  D). Transverse because of the direction that the wave is traveling.

EXPLANATION:

Before going to answer this question, first we have to understand the nature of transverse and longitudinal wave.

A transverse wave (except light) is a type of mechanical wave in which the direction of vibration of particles is perpendicular to the direction of wave propagation. This type of wave is propagated in a medium in the form of crests and troughs.

A longitudinal wave is a type of mechanical wave in which the direction of vibration of particles is parallel to the wave propagation.  This type of wave is propagated in the form of compression and rarefaction. Compression is the high pressure region in a wave where particles are very close to each other, and rarefaction is the low pressure region where particles are far away from each other.

As per the question, the particles of the medium are displaced perpendicular to the wave motion. Hence, the wave will be  transverse in nature.

allochka39001 [22]3 years ago
4 0

Answer:

The answer is B

Explanation:

I just took the test and found out that D is the WRONG answer choice. I do agree that it is a transverse wave though, so it would be B.

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Answer:

Option C or the third option.

Explanation: Water is a renewable resource there is so much of it and it just keeps circulating through the system it doesn't run out.

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4 years ago
A steel ball rolls with a constant velocity on a tabletop 0.950 m high it rolls off and hit the ground 0.352 m from the edge of
sp2606 [1]

Answer:

0.799 m/s if air resistance is negligible.

Explanation:

For how long is the ball in the air?

Acceleration is constant. The change in the ball's height \Delta h depends on the square of the time:

\displaystyle \Delta h = \frac{1}{2} \;g\cdot t^{2} + v_0\cdot t,

where

  • \Delta h is the change in the ball's height.
  • g is the acceleration due to gravity.
  • t is the time for which the ball is in the air.
  • v_0 is the initial vertical velocity of the ball.
  • The height of the ball decreases, so this value should be the opposite of the height of the table relative to the ground. \Delta h = -0.950\;\text{m}.
  • Gravity pulls objects toward the earth, so g is also negative. g \approx -9.81\;\text{m}\cdot\text{s}^{-2} near the surface of the earth.
  • Assume that the table is flat. The vertical velocity of the ball will be zero until it falls off the edge. As a result, v_0 = 0.

Solve for t.

\displaystyle \Delta h = \frac{1}{2} \;g\cdot t^{2} + v_0\cdot t;

\displaystyle -0.950 = \frac{1}{2} \times (-9.81) \cdot t^{2};

\displaystyle t^{2} =\frac{-0.950}{1/2 \times (-9.81)};

t \approx 0.440315\;\text{s}.

What's the initial horizontal velocity of the ball?

  • Horizontal displacement of the ball: \Delta x = 0.352\;\text{m};
  • Time taken: \Delta t = 0.440315\;\text{s}

Assume that air resistance is negligible. Only gravity is acting on the ball when it falls from the tabletop. The horizontal velocity of the ball will not change while the ball is in the air. In other words, the ball will move away from the table at the same speed at which it rolls towards the edge.

\begin{aligned}\text{Rolling Velocity}&=\text{Horizontal Velocity} \\&= \text{Average Horizontal Velocity}\\ &=\frac{\Delta x}{\Delta t}=\frac{0.352\;\text{m}}{0.440315\;\text{s}}=0.0799\;\text{m}\cdot\text{s}^{-1}\end{aligned}.

Both values from the question come with 3 significant figures. Keep more significant figures than that during the calculation and round the final result to the same number of significant figures.

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spayn [35]
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Two water jets are emerging from a vessel at a height of 50 centimeters and 100 centimeters. If their horizontal velocities at t
givi [52]
For t1:

t1 = square root of 2h1 / g = square root of 2 * 0.5 / 9.8 = 0.319 sec

For t2:

t2 = sqaure root of 2h2 / g = square root of 2 * 1.0 / 9.8 = 0.451 sec

Wherein:
t = time(s) for the vertical movement
h= height
g = gravity (using the standard 9.8 m/sec measurement)

d1 = 1*0.319 = 0.319 m
d2 = 0.5 * 0.451 = 0.225 m

Where:

d = hor. distance

ratio = d1:d2
= 0.319 : 0.225
=3.19 : 2.25

The answer is 3.19 : 2.25
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