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natulia [17]
3 years ago
13

What is the number of formula units in a 5.53 mol sample of NH4NO3?

Chemistry
1 answer:
Iteru [2.4K]3 years ago
6 0
5.53*(6.023*10^23)= 33.30*10^27
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Hello,

In this case, with the following obtained results, the percent error is computed as follows:

Volume of vinegar= 7.0 mL

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Concentration of acetic acid= (concentration of NaOH*volume of NaOH)/volume of vinegar= (6.7mL*1.5M)/7.0M= 1.44M

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Clearly, this result depend on your own measurements, anyway, you can change any value wherever you need it.

Regards.

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