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kupik [55]
3 years ago
7

2NaOH+CO2----->Na2CO3+H2O

Chemistry
1 answer:
kondaur [170]3 years ago
8 0

Answer:

13.2 g Na2CO3

Explanation:

Convert 10.0 g NaOH to mol.

10.0 g x 1 mol/39.997 g = 0.250 mol

Use mol ration given by the equation: 2 mol NaOH to 1 mol Na2CO3

0.250 mol NaOH x 1 mol Na2CO3/2 mol NaOH = 0.125 mol Na2CO3

Finally, convert the moles of Na2CO3 to grams.

0.125 mol Na2CO3 x 105.99 g/1 mol = 13.2 g

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Determine the mass of oxygen in a 7.2- g sample of A l 2 (S O 4 ) 3 .
astraxan [27]
Molar mass of A l 2 (S O 4 ) 3 = 342.15 g/mol
7.2g/ 342.15 g/mol
you can get number of moles.
then multiply that by12
7 0
3 years ago
What properties distinguish solids from liquids liquids from gases solids from gases?
Gala2k [10]

In a solid, the molecules are packed together, keeping shape. Liquid molecules are looser, and fit to the container they are in. Gas molecules are sporadic, and expand to fit their container

5 0
3 years ago
Read 2 more answers
A 1.0 L container holds a sample of hydrogen gas at 300 K and 101.5 k Pa. If the pressure increases to 508 k Pa and the volume r
ankoles [38]

<u>Answer:</u> The temperature will be 1501.47 K.

<u>Explanation:</u>

To calculate the temperature of the gas when pressure is increased, we use the equation given by Gay-Lussac's Law.

This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

Mathematically,

P\propto T

or,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and initial temperature of the gas.

P_2\text{ and }T_2 are the final pressure and final temperature of the gas.

We are given:

P_1=101.5kPa\\T_1=300K\\P_2=508kPa\\T_2=?K

Putting values in above equation, we get:

\frac{101.5kPa}{300K}=\frac{508kPa}{T_2}\\\\T_2=1501.47K

Hence, the temperature will be 1501.47 K

4 0
3 years ago
A 0.552-g sample of ascorbic acid (vitamin C) was dissolved in water to a total volume of 20.0 mL and titrated with 0.1103 M KOH
Tanzania [10]

Answer:

176.36g/mol

Explanation:

It was given that:

Mass of ascorbic acid=0.552 g

Volume of water=20.0 mL

Concentration of KOH=0.1103 M

Volume of KOH=28.42 mL. = 0.02842l

pH of solution at 10.0 mL= 3.72

At equivalence point, number of moles of acid is equal to the number of moles of base.

Number of moles of base= (KOH) x Volume

                        =0.1103 x 0.02842 L

                                =0.00313 moles.

Therefore number of miles of acid= 0.00313moles

No of moles= Mass/molar mass

Molar Mass= Mass of Acid/ No of moles of acid

= 0.552g/0.00312moles

= 176.36g/mol

4 0
3 years ago
Name three different kind of solar satellites.
saul85 [17]

Answer:

Planets, asteroids, and comets

Explanation:

7 0
3 years ago
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