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Dovator [93]
3 years ago
11

A tungsten wire has resistance R at 20°C. A second tungsten wire at 20°C has twice the length and half the cross-sectional area

of the first wire. In terms of R, the resistance of the second wire is
Physics
1 answer:
Colt1911 [192]3 years ago
8 0

Answer:

Resistance will become 4 times of first wire resistance.

Explanation:

At the temperature of both the the tungsten wire is same so we can apply ohm's law

Let the length of first wire is l_1 and cross sectional area is A_1

Resistance of first wire R=\frac{\rho l_1}{A_1}......1

Now length of second wire is twice the length of first wire

l_2=2l_1 and cross sectional area A_2=\frac{A_1}{2}.......2

Resistance of wire 2 R_2=\frac{\rho l_2}{A_2}........2

Dividing equation 1 by equation 1

\frac{R}{R_2}=\frac{\rho l_1}{A_1}\times \frac{0.5A_1}{\rho 2l_1}

R_2=4R

Therefore resistance will become 4 times.

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