It is fairly easy to build an electromagnet. All you need to do is wrap some insulated copper wire around an iron core. If you attach a battery to the wire, an electric current will begin to flow and the iron core will become magnetized. When the battery is disconnected, the iron core will lose its magnetism.
The size and the explosion
Answer:
R = 42.67 ohms
Explanation:
It is given that, a thin-filament light bulb is connected to two 1.6 V batteries in series, the current is 0.075 A.
It means that when two batteries are connected in series, then the total voltage is 3.2 volts
Let R is the resistance of the glowing thin-filament bulb. So, using Ohm's law we get :
So,
So, the resistance of the bulb is 42.67 ohms.
The electrostatic force is 9 x 10¯³ N.
We need to know about electrostatic force to solve this problem. The electrostatic force is applied on a charge which has near position to another charge. It can be determined by
F = k Q1 . Q2 / r²
where F is electrostatic force, k is Coulomb constant (9 x 10⁹ Nm²/C²), Q1 and Q2 are the charges and r is the radius or distance between the charges.
From the question above, we know that
Q1 = -10 nC = -10 x 10¯⁹ C
Q2 = -10 nC = -10 x 10¯⁹ C
r = 1 cm = 0.01 m
By substituting the following parameters, we can calculate the electrostatic force
F = k Q1 . Q2 / r²
F = (9 x 10⁹ . 10 x 10¯⁹ . 10 x 10¯⁹ / (0.01)²
F = 9 x 10¯³ N
Hence, the electrostatic force is 9 x 10¯³ N.
Find more on electrostatic force at: brainly.com/question/17692887
#SPJ4
B is the answer to this problem
