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disa [49]
3 years ago
7

Follow TwitchTestingAccount1 on twitch.tvFOLLOW AND TELL UR FRIENDS

Chemistry
2 answers:
inysia [295]3 years ago
3 0

Answer:

xd wow so you just use this for publicity

Explanation:

XD ly

Katena32 [7]3 years ago
3 0

Answer:

Ok sure i can

Explanation:

If u want me to that is.

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PLEASE ANSWER QUESTION 6!!
kap26 [50]

Explanation:

MD: 242 364 7480

Ps: TYSON all can come for talking about

5 0
2 years ago
How many days does it take 16.Og of Gold-198 to decay to 1.0g? (each half-
forsale [732]

Answer:

10.8 days (3 sig.figs.)

Explanation:

All radioactive decay is 1st order decay defined by the expression A = A₀e^-kt

which is solved for time of decay (t) => t = ln(A/A₀) / -k

A = final weight = 1.0 gram

A₀ = initial weight = 16.0 grams

k = rate constant = 0.693/t(1/2) = 0.693/2.69 days = 0.258 days⁻¹

t = ln(1/16) / -0.258da⁻¹ = (-2.77/-0.258) days = 10.74646792 days (calculator)

≅ 10 days (1 sig. fig. based on given 1 gram mass)

4 0
2 years ago
Why is water considered a pure substance and not a mixture?
Minchanka [31]
Water is made of only one molecule which can be chemically separated into hydrogen and oxygen. The answer is D.
5 0
3 years ago
Read 2 more answers
The molarity of a solution prepared by dissolving 4.11 g of NaI in enough water to prepare 312 mL of solution is
Dimas [21]

Answer:

The correct answer is 8.79 × 10⁻² M.

Explanation:

Based on the given information, the mass of NaI given is 4.11 grams. The molecular mass of NaI is 149.89 gram per mole. The moles of NaI can be determined by using the formula,

No. of moles of NaI = Weight of NaI/ Molecular mass

= 4.11 / 149.89

= 0.027420

The vol. of the solution given is 312 ml or 0.312 L

The molarity can be determined by using the formula,

Molarity = No. of moles/ Volume of the solution in L

= 0.027420/0.312

= 0.0879 M or 8.79 × 10⁻² M

6 0
2 years ago
Which of the following is the strongest base? ta) CH,ONa (b) NaNH, (c) CH-CH,Li (0) NaOH (6) CHÚCONa
Mashutka [201]

Hey there:

Correct answer is :

(b) NaNH₂

Sodium azanide NaNH₂ is the conjugate base of ammonia NH₃

Correct answer is :

(b) NaNH₂

I hope this will help !

7 0
3 years ago
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