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2 years ago

Hi i want to know if sex cells ever develop into regular cells

Chemistry

2 answers:

mezya [45]2 years ago

8 0

No, sex cells are always sex cells

LekaFEV [45]2 years ago

5 0

I believe they don't because once something is something, it can never change

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A police car is approaching the corner. Explain what happens to the frequency of sound as it draws closer. What will you hear?

barxatty [35]

The frequency stays the same it just gets louder

8 0

2 years ago

A chemistry student needs to standardize a fresh solution of sodium hydroxide. He carefully weighs out 28.mg of oxalic acid H2C2

Nezavi [6.7K]

Answer:

The molarity of the student's sodium hydroxide solution is 0.0219 M

Explanation:

1) Chemical reaction.

a) Kind of reaction: neutralization

b) General form: acid + base → salt + water

c) Word equation:

sodium hydroxide + oxalic acid → sodium oxalate + water

d) Chemical equation:

NaOH + H₂C₂O₄ → Na₂C₂O₄ + H₂O

b) Balanced chemical equation:

2NaOH + H₂C₂O₄ → Na₂C₂O₄ + 2H₂O

2) Mole ratio

2mol Na OH : 1 mol H₂C₂O₄ :1 mol Na₂C₂O₄ : 2 mol H₂O

3) Starting amount of oxalic acid

mass = 28 mg = 0.028 g
molar mass = 90.03 g/mol
Convert mass in grams to number of moles, n:

n = mass in grams / molar mass = 0.028 g / 90.03 g/mol = 0.000311 mol

4) Titration

Volume of base: 28.4 mL = 0.0248 liter
Concentration of base: x (unknwon)

Number of moles of acid: 2.52 mol (calculated above)

Proportion using the theoretical mole ratio (2mol Na OH : 1 mol H₂C₂O₄)

$\frac{2}{1} =\frac{x}{2.52}\\ \\ \\x=0.000311(2)=0.000622$

That means that there are 0.000622 moles of NaOH (solute)

5) Molarity of NaOH solution

M = n / V (liter) = 0.000622 mol / 0.0284 liter = 0.0219 M

That is the correct number using three signficant figures, such as the starting data are reported.

5 0

2 years ago

Read 2 more answers

Many homeowners treat their lawns with CaCO3(s) to reduce the acidity of the soil. Write a net ionic equation for the reaction o

Aliun [14]

Many homeowners treat their lawns with CaCO3(s) to reduce the acidity of the soil. The net ionic equation for the reaction of CaCO3(s) with a strong acid, HCl (I chose HCl because it is a strong acid) is CaCO3(s) +2 HCl(aq) → CaCl2(s) + H2O(aq) + CO2(g).

3 0

2 years ago

What fraction of the original atoms of the radioactive sample will remain after the given number of half-lives has passed?

meriva

Answer:

1/8

Explanation:

$\frac{1}{ {2}^{3} } = \frac{1}{8}$

Mark brainliest please

5 0

1 year ago

How to prepare magnesium carbonate starting with magnesium nitrate

STALIN [3.7K]

Answer:

How to prepare Magnesium Carbonate:

Explanation:

Magnesium carbonate can be prepared in laboratory by reaction between any soluble magnesium salt and sodium bicarbonate: MgCl2(aq) + 2NaHCO3(aq) → MgCO3(s) + 2NaCl(aq) + H2O(l) + CO2(g)

8 0

2 years ago