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IrinaVladis [17]
3 years ago
13

A fancart of mass 0.8 kg initially has a velocity of < 0.9, 0, 0 > m/s. Then the fan is turned on, and the air exerts a co

nstant force of < -0.3, 0, 0 > N on the cart for 1.5 seconds. What is the change in momentum of the fancart over this 1.5 second interval? = < , 0, 0 > kg
Physics
1 answer:
Dmitry [639]3 years ago
6 0

Answer:

<-0.45, 0, 0> kgm/s

Explanation:

The change in momentum would equal to the impulse generated by force F = <-0.3, 0, 0> over time duration of Δt = 1.5 second. The impulse is defined as the product of force F and the duration Δt

\Delta p = F \Delta t = (-0.3) * 1.5 = -0.45 kgm/s

So the change in momentum is <-0.45, 0, 0> kgm/s

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Select the option that best summarizes the reason for the use of position-time graphs when studying physical science. (1 point)
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<h3>What is velocity?</h3>

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4 0
1 year ago
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Which of the following best describes how galaxies exist in the universe?
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We divide the electromagnetic spectrum into six major categories of light, listed below. Rank these forms of light from left to
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5 0
3 years ago
A<br> B <br> C <br> D<br><br> Plz help me.
Montano1993 [528]

Answer:

The correct option is;

{}               Man doing most work   {}    Box gaining the most energy

D   {}                 Y                                          Q

Explanation:

The given parameters of the question are;

The distance the box P is pushed by the Man X = 0

The force the Man X applies to the box P = x N

The distance the box Q is lifted by the Man Y = h > 0 meters

The minimum force the Man Y applies to the box Q = W, the weight of the box

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Energy gained = Potential energy + Kinetic Energy = (Mass × Gravity × Height = Weight × Height  = W × h) + 1/2 × Mass × Velocity²

The final velocity of either box = 0 m/s (The boxes are at rest on the ground or the shelf)

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The work done by Man X = 0 × x = 0 J

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The energy gained by the box P = W × h = W·h J

We have, the work done by the man Y = W·h J is more than the work done by the man X = 0 J

The energy gained by the box P = W·h J is more than the energy gained by the box Q = 0 J

Therefore, the correct option is D, Man doing the most work is Y, box gaining the most energy is Q.

8 0
2 years ago
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