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IrinaVladis [17]
2 years ago
13

A fancart of mass 0.8 kg initially has a velocity of < 0.9, 0, 0 > m/s. Then the fan is turned on, and the air exerts a co

nstant force of < -0.3, 0, 0 > N on the cart for 1.5 seconds. What is the change in momentum of the fancart over this 1.5 second interval? = < , 0, 0 > kg
Physics
1 answer:
Dmitry [639]2 years ago
6 0

Answer:

<-0.45, 0, 0> kgm/s

Explanation:

The change in momentum would equal to the impulse generated by force F = <-0.3, 0, 0> over time duration of Δt = 1.5 second. The impulse is defined as the product of force F and the duration Δt

\Delta p = F \Delta t = (-0.3) * 1.5 = -0.45 kgm/s

So the change in momentum is <-0.45, 0, 0> kgm/s

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Explanation:

It is given that,

Diameter of the peach pie, d = 9 inches

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Let \theta is the angular distance that the pie plate has moved through.

It is given by :

\theta=\dfrac{d}{r}

\theta=\dfrac{183}{4.5}  

\theta=40.66\ radian

Since, 1 radian = 57.29 degrees

\theta=2329.64\ degrees

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Hence, this is the required solution.

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3 years ago
How do the current and coltage readings compare to before the wires were switched. Explain how to interpret them physically?
Blababa [14]
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  • If the electricity passes through the voltmeter it shows deflection.

<h3>What is the purpose of a voltmeter?</h3>
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<h3>What is the explanation for the link between current and voltage?</h3>
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7 0
1 year ago
A circuit consists of a 12 V battery connected across a single resistor. If the current in the circuit is
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Answer:

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Explanation:

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You can change it the way you want to use for your purpose.

In this case...

R = V/I

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R = 4 Ohms (Ohm is the unit of measurement of eletrical resistance)

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2 years ago
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3 years ago
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