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Bingel [31]
3 years ago
13

Consider a stone at rest on the ground. There are two interactions that involve the stone. One is between the stone and the Eart

h; Earth pulls down on the stone and the stone pulls up on the Earth. What is the other interaction? 1. All are wrong. 2. between the ground and the Earth 3. between the ground and air 4. between the Earth and air 5. between the stone and the ground
Physics
1 answer:
finlep [7]3 years ago
3 0

5. between the stone and the ground

for a stone at rest on the ground, we have two forces acting on the stone. first is the force on the stone by the earth due to gravity of earth. second is the force applied by the ground in upward direction to balance the force of gravity on the stone.

so first interaction is between earth and stone : earth pulls stone towards it and stone pulls earth towards it by same amount of force.

second interaction is between stone and ground : ground push the stone in upward direction and stone push the ground in down direction by same amount of force.

hence the correct choice is

5. between the stone and the ground

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lesya [120]

Answer:

Explanation:

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The steps and appropriate calculation is as shown in the attached file.

6 0
3 years ago
A black, totally absorbing piece of cardboard of area a = 2.1 cm2 intercepts light with an intensity of 8.8 w/m2 from a camera s
PolarNik [594]

Answer:

The value of radiation pressure is 2.933 \times 10^{-8} Pa

Explanation:

Given:

Intensity I = 8.8 \frac{W}{m^{2} }

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From the formula of radiation pressure in terms of intensity,

   P = \frac{I}{c}

Where P = radiation pressure, c = speed of light

We know value of speed of light,

 c = 3 \times 10^{8} \frac{m}{s}

Put all values in above equation,

  P = \frac{8.8}{3 \times 10^{8} }

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Therefore, the value of radiation pressure is 2.933 \times 10^{-8} Pa

8 0
3 years ago
Light bulb 1 operates with a filament temperature of 2700 K whereas light bulb 2 has a filament temperature of 2100 K. Both fila
Lemur [1.5K]

Answer:

0.3659

Explanation:

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P = AeσT⁴

where,

A =Area

e = transmittivity

σ = Stefan-boltzmann constant

T = Temperature

since both the bulbs radiate same power

P₁ = P₂

Where, 1 denotes the bulb 1

2 denotes the bulb 2

thus,

A₁e₁σT₁⁴ = A₂e₂σT₂⁴

Now e₁=e₂

⇒A₁T₁⁴ = A₂T₂⁴

or

\frac{A_1}{A_2} =\frac{T_{2}^{4}}{T_{1}^{4}}

substituting the values in the above question we get

\frac{A_1}{A_2} =\frac{2100_{2}^{4}}{2700_{1}^{4}}

or

\frac{A_1}{A_2} }=0.3659

6 0
3 years ago
A machine that operates a ride at the fair requires 2500 J to lift a 294 N child 5.0 m. What is the efficiency of this machine?
NeX [460]

Answer:

η = 58.8%

Explanation:

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W =F*d

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W = work [J] (units of joules)

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Efficiency is defined as the energy required to perform an activity in relation to the energy actually added to perform some activity. This can be better understood by means of the following equation.

efficiency = W_{done}/W_{required}\\efficiency = 1470/2500\\efficiency = 0.588 = 58.8%

5 0
2 years ago
Marcus tells Sabrina that for the last few months, he has not been able to detect moderate heat or cold with his fingertips. Whi
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There are different types of nerve endings, particularly the ones responsible to detect pain, and temperature are the free nerve endings.

So Marcus may have the free nerve endings damaged.

4 0
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