The speed of the brick dropped by the builder as it hits the ground is 17.32m/s.
Given the data in the question;
Since the brick was initially at rest before it was dropped,
- Initial Velocity;  
- Height from which it has dropped;  
- Gravitational field strength;  
Final speed of brick as it hits the ground; 
<h3>Velocity</h3>
velocity is simply the same as the speed at which a particle or object moves. It is the rate of change of position of an object or particle with respect to time. As expressed in the Third Equation of Motion:

Where v is final velocity, u is initial velocity, h is its height or distance from ground and g is gravitational field strength. 
To determine the speed of the brick as it hits the ground, we substitute our giving values into the expression above. 

Therefore, the speed of the brick dropped by the builder as it hits the ground is 17.32m/s.
Learn more about equations of motion: brainly.com/question/18486505
 
        
             
        
        
        
Answer:
a)Yes will deform plastically
b) Will NOT experience necking
Explanation:
Given:
 - Applied Force F = 850 lb
 - Diameter of wire D = 0.15 in
 - Yield Strength Y=45,000 psi
 - Ultimate Tensile strength U = 55,000 psi 
Find:
a) Whether there will be plastic deformation
b) Whether there will be necking.
Solution:
Assuming a constant Force F, the stress in the wire will be:
                        stress = F / Area
                        Area = pi*D^2 / 4
                        Area = pi*0.15^2 / 4 = 0.0176715 in^2
                        stress = 850 / 0.0176715
                        stress = 48,100.16 psi 
       Yield Strength < Applied stress > Ultimate Tensile strength
                         45,000 < 48,100 < 55,000
Hence, stress applied is greater than Yield strength beyond which the wire will deform plasticly but insufficient enough to reach UTS responsible for the necking to initiate. Hence, wire deforms plastically but does not experience necking.
 
        
             
        
        
        
There are several information's of immense importance already given in the question. Based on the given information's the answer to the question can easily be determined.
Distance covered by the bicycle = 5000 meter
Time taken by the bicycle to reach the distance = 500 second.
Velocity of the bicycle = Distance / Time taken
                                   = 5000/500 meter/second
                                   = 50 meter/second
So the velocity of the bicycle is 50 meter per second. I hope the procedure is clear enough for you to understand. In future you can always use this procedure for solving similar problems.
        
             
        
        
        
Answer:
ANSWERS ARE 100 % correct
Explanation:
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