Answer:
145.97×10²³ atoms
Explanation:
Given data:
Number of moles of CO₂ = 8.08 mol
Number of atoms of CO₂ = ?
Solution:
1 mole of CO₂ contain 1 mole C atom.
8.08 mole contain 8.08× 1 = 8.08 mole of C atom.
1 mole of CO₂ contain 2 moles of O atom.
8.08mole contain 8.08×2 = 16.16 mole of O atom.
Total number of moles of atoms = 8.08 mole + 16.16 mole
Total number of moles of atoms = 24.24 mol
Number of atoms of CO₂:
1 mole of any substance contain 6.022×10²³ atoms.
24.24 mol ×6.022×10²³ atoms / 1 mol
145.97×10²³ atoms
Answer:
It's 3-Methylhexane.
Explanation:
The only way I can explain this is to say you need to draw out the Lewis structure and find out what it is. Or if they don't give you the composition of the molecules then you'll have to memorize the structures.
Answer:
16.95 g of LiCl and 28.4 g of Na₂SO₄.
Explanation:
- The reaction between NaCl and Li₂SO₄ is represented as:
<em>2NaCl + Li₂SO₄ → 2LiCl + Na₂SO₄.</em>
- it is clear that 2.0 moles of NaCl react with 1.0 mole of Li₂SO₄ to produce 2.0 mole of LiCl and 1.0 mole of Na₂SO₄.
- We need to calculate the no. of moles of NaCl (23.45 g) and Li₂SO₄ (56.23 g) using the relation:
<em>n = mass/molar mass,</em>
n of NaCl = mass/molar mass = (23.45 g)/(58.44 g/mol) = 0.40 mol.
n of Li₂SO₄ = mass/molar mass = (56.23 g)/(109.94 g/mol) = 0.51 mol.
- <em>Since, every 1.0 mole of Li₂SO₄ reacts with 2.0 moles of NaCl, so 0.2 mole of Li₂SO₄ will react with 0.4 mol of NaCl.</em>
<em>∴ NaCl is the limiting reactant and Li₂SO₄ is in excess.</em>
- So, the products will be LiCl (0.4 mol) and Na₂SO₄ (0.2 mol).
- Now, we can get the masses of each product using the relation:
<em>mass = n x molar mass.</em>
∴ mass of LiCl = n x molar mass = (0.4 mol)(42.394 g/mol) = 16.95 g.
∴ mass of Na₂SO₄ = n x molar mass = (0.2 mol)(142.04 g/mol) = 28.4 g.