Answer:
Planetary orbits are all nearly circular , comet orbits are highly excentric . ... This means that planets stay more or less at the same distance from the sun, while comets travel as far out as beyond Neptune, and can travel as far in as Mercury.
The addition of bromine would cause the equilibrium to shift towards the reactant's side.
<h3>Equilibrium</h3>
When a reaction is in equilibrium and one of the constraints that affect the rate of reactions is applied, the equilibrium shifts so as to annul the effects of the introduced constraints.
Thus, for the reaction
NaBr(s) ⇌ Na+(aq) + Br−(aq)
The addition of HBr would introduce more Br- into the reaction. Consequently, the equilibrium will shift to produce more NaBr so as to annul the effects of the addition of Br-
More on equilibrium can be found here: brainly.com/question/4289021
Answer:
See the answer below
Explanation:
Distillation is a process of separating the contents of a liquid mixture by making use of the difference in the boiling temperatures of the components of the mixture. As the boiling point of each component is reached, it evaporates off and the vapor is condensed and collected to give a pure product.
<em>It is never advisable to distillate to dryness because allowing the content of the distilling flask to dry up can cause heat to damage the flask or in some extreme cases, cause unintended chemical reactions that might alter the outcome of the experiment or cause laboratory accident.</em>
Answer:
Fractional distillation
Explanation:
Heat the mixture upto 700°C
The compuond with low boiling point will evaporate first and the compound with higher boiling point will evaporate last.
Answer:
2Rb(s) + Sr^+(aq) → 2Rb^+ (aq) + Sr(s)
Explanation:
Rubidium has a more negative reduction potential (-2.98 V) compared to strontium (-2.89 V).
Hence, in a redox reaction involving rubidium and strontium, rubidium will be oxidized while strontium is reduced.
The balanced redox reaction equation is obtained from;
Oxidation half equation;
2Rb(s) ---->2Rb^+(aq) + 2e
Reduction half equation;
Sr^2+(aq) + 2e ----> Sr(s)
Overall reaction equation;
2Rb(s) + Sr^+(aq) → 2Rb^+ (aq) + Sr(s)