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Anon25 [30]
3 years ago
8

What objects do balanced forces act on?

Physics
1 answer:
leva [86]3 years ago
4 0

Answer: Stationary or constant velocity

Explanation:

Objects with balanced forces acting on them experience no change in motion, or no acceleration. So these objects could either be stationary at rest or have a constant velocity. These include a hanging object, a floating object, an object on a table that doesn't move, and a car moving at a constant 10 mph

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Your friend says that for a moving object to continue moving, a force must be continually applied to it. Do you agree with your
Zigmanuir [339]

Answer:

I would disagree with my friend because that according to Newton's first law, an object in motion will continue to be in motion until stopped by another object/force. If the object is already moving, it will stay in motion until something else stops it. There is no need for a force to be <em>continually</em> applied to it while it's already moving.

4 0
2 years ago
An AC generator supplies 44 rms volts to a 60-Ω resistor at 60 Hz. What is the maximum current in the resistor?
Brilliant_brown [7]

Answer:

1.0639 A

Explanation:

We have given rms voltage V = 44 volt

Resistance = 60 ohm

According to ohm's law V=iR

So 44=i\times 60

i=\frac{44}{60}=0.7333A this is the rms current but we have to find the maximum current

So maximum current i_m=\sqrt{2}i_{rms}=1.414\times 0.7333=1.03693A

8 0
4 years ago
Four identical masses of 2.5 kg each are located at the corners of a square with 1.0-m sides. What is the net force on any one o
Ghella [55]

Answer:

F=8.0*10^{-10}N

Explanation:

See the attached file for the masses distributions

The force between two masses at distance r is expressed as

F=\frac{Gm_{1}m_{2}  }{r^{2} }\\ G=Gravitional constant \\

since the masses are of the same value, the above formula can be reduce to

F=\frac{Gm^{2}}{r^{2} }\\

using vector notation,Let use consider the force on the lower left corner of the mass due to the upper left side of the mass is

F_{12} =\frac{Gm^{2}}{r^{2} }j\\

The force on the lower left corner of the mass due to the lower right side of the mass is

F_{14} =\frac{Gm^{2}}{r^{2} }i\\

The force on the lower left corner of the mass due to the upper right side of the mass is

F_{13} =\frac{Gm^{2}}{d^{2} }cos\alpha i +\frac{Gm^{2}}{d^{2} }sin\alpha j\\

The net force can be express as

F=\frac{Gm^{2}}{r^{2} }j +\frac{Gm^{2}}{r^{2} }i +\frac{Gm^{2}}{d^{2} }cos\alpha i +\frac{Gm^{2}}{d^{2} }sin\alpha j\\\\F=Gm^{2}[\frac{1}{r^{2}}+ \frac{1}{d^{2}cos\alpha }]i + Gm^{2}[\frac{1}{r^{2}}+ \frac{1}{d^{2}sin\alpha }]j\\\alpha=45^{0}, G=6.67*10^{-11}Nmkg^{-2}

if we insert values we arrive at

F=6.67*10^{-11}*2.5^{2}[\frac{1}{1^{2}}+ \frac{1}{\sqrt{2}^{2}cos45 }]i + 6.67*10^{-11}*2.5^{2}[\frac{1}{1^{2}}+ \frac{1}{\sqrt{2}^{2}sin45}]j\\F=5.643*10^{-10}i+5.643*10^{-10}j

if we solve for the magnitude, we arrive at

F=5.643*10^{-10}i+5.643*10^{-10}j \\F=\sqrt{(5.643*10^{-10})^{2} +(5.643*10^{-10})}^{2} \\F=8.0*10^{-10}

Hence the net force on one of the masses is

F=8.0*10^{-10}N

8 0
3 years ago
find the pressure exerted by a force of 8000 newtons on an area of 25m square..give your answer in Newtown/m2​
baherus [9]

Answer:

Pressure = 320 N/m²

Explanation:

Given the following data;

Force = 8000 Newton

Area = 25 m²

To find the pressure, we would use the following formula;

Pressure = force/area

Substituting into the formula, we have;

Pressure = 8000/25

Pressure = 320 N/m²

5 0
3 years ago
A 1000 kg boat starts at rest and accelerates to 10 m/s in 2 seconds. How fast does the boat accelerate?
Hitman42 [59]

Answer:

5 m/s^2

Explanation:

The acceleration of an object is given by

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time it takes for the velocity to change from u to v

For the boat in the problem,

v = 10 m/s

u = 0

t = 2 s

Substituting, we find the acceleration

a=\frac{10-0}{2}=5 m/s^2

5 0
3 years ago
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