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Anon25 [30]
3 years ago
8

What objects do balanced forces act on?

Physics
1 answer:
leva [86]3 years ago
4 0

Answer: Stationary or constant velocity

Explanation:

Objects with balanced forces acting on them experience no change in motion, or no acceleration. So these objects could either be stationary at rest or have a constant velocity. These include a hanging object, a floating object, an object on a table that doesn't move, and a car moving at a constant 10 mph

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Like windmills they use the winds to generate their power.
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3 years ago
An object is 3.0 cm from a concave mirror, with a focal length of 1.5 cm. Calculate the image distance. Remember to include your
Sunny_sXe [5.5K]

Answer:

Construct a quadrilateral ABCD, where

Construct a quadrilateral ABCD, whereAB = 4 cm, BC = 5 cm, CD = 6.5 cm and angle B = 105° and angle C = 80°

7 0
3 years ago
a body initially at rest, starts moving with a constant acceleration of 2ms-2 .calculate the velocity acquired and the distance
Marta_Voda [28]

a) 10 m/s

b) 25 m

Explanation:

a)

The body is moving with a constant acceleration, therefore we can solve the problem by using the following suvat equation:

v=u+at

where

u is the initial velocity

v is the final velocity

a is the acceleration

t is the time

For the body in this problem:

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

t = 5 s is the time

So, the final velocity is

v=0+(2)(5)=10 m/s

b)

In this second part, we want to calculate the distance travelled by the body.

We can do it by using another suvat equation:

v^2-u^2=2as

where

u is the initial velocity

v is the final velocity

a is the acceleration

s is the distance travelled

Here we have

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

v = 10 m/s is the final velocity

Solving for s,

s=\frac{10^2-0^2}{2(2)}=25 m

3 0
3 years ago
Is this a boy or a girl
ivanzaharov [21]

I believe that it is a boy but if they would like to be classified as a girl or a boy their decision needs to be respected

3 0
3 years ago
A migrating robin flies due north with a speed of 12 m/s relative to the air. The air moves due east with a speed of 6.7 m/s rel
mafiozo [28]

Here it is given that speed of migrating Robin is 12 m/s relative to air

so we can say that

\vec v_{ra} = 12 m/s North

so it will be

Let North direction is along Y axis and East direction is along X axis

\vec v_{ra} = 12\hat j

also it is given that speed of air is 6.7 m/s relative to ground

\vec v_a = 6.7 \hat i

now as we know by the concept of relative motion

\vec v_{ab} = \vec v_a - \vec v_b

\vec v_{ra} = \vec v_r  - \vec v_a

now by rearranging the terms

\vec v_r = \vec v_{ra} + \vec v_a

\vec v_r = 12 \hat j + 6.7 \hat i

now we need to find the speed of Robin which means we need to find the magnitude of its velocity which we found above

So here we will say

v_r = \sqrt{12^2 + 6.7^2}

v_r = 13.7 m/s

so the net speed of Robin with respect to ground will be 13.7 m/s

7 0
3 years ago
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