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lyudmila [28]
2 years ago
7

If a car change the velocity from 36M/S to 28M/S with an acceleration of -2.0 M/S then how much time does it take for the vehicl

e to slow down? please help I NEDD it fasstttt
Physics
1 answer:
leonid [27]2 years ago
6 0

The time it will take if a car change the velocity from 36m/s to 28m/s with an acceleration of -2.0m/s² is 4s.

<h3>How to calculate deceleration?</h3>

Deceleration is the amount by which a speed or velocity decreases (and so a scalar quantity or a vector quantity).

The deceleration of a body can be calculated using the following formula:

-a = (v - u)/t

Where;

  • -a = deceleration
  • v = final velocity
  • u = initial velocity
  • t = time in seconds

-2 = (28 - 36)/t

-2t = -8

t = 4s

Therefore, the time it will take if a car change the velocity from 36m/s to 28m/s with an acceleration of -2.0m/s² is 4s.

Learn more about deceleration at: brainly.com/question/4403243

#SPJ1

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Answer:

Initial velocity describes how fast an object travels when gravity first applies force on the object. On the other hand, the final velocity is a vector quantity that measures the speed and direction of a moving body after it has reached its maximum acceleration.

Explanation:

3 0
2 years ago
Passengers on an airplane move from rest to 86 meters per second before the airplane takes off. If the airplane takes 100 second
VikaD [51]

Utilize the formula:  V _{f} = V _{i} + a\Delta t

V _{f} = Final Velocity (86 m/s)

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As a result,

86 m/s = 0 + (a)(100 seconds)

Using algebra, divide 86 m/s by 100 seconds:

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4 0
3 years ago
Three conducting plates, each of area A, are connected as shown.
Shkiper50 [21]
You have effectively got two capacitors in parallel. The effective capacitance is just the sum of the two. 
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But I suppose we ought to kick that idea around a bit. 
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C = ε₀AD / d₁d₂ We can also say: d₂ = D - d₁ C = ε₀AD / d₁(D - d₁) C = ε₀AD / d₁D - d₁² 
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In other words when the middle plate is halfway between the two outer plates, (quelle surprise) so that 
d₁ = d₂ = ½D so 
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3 0
3 years ago
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