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yaroslaw [1]
3 years ago
12

Two oppositely charged but otherwise identical conducting plates of area 2.50 square centimeters are separated by a dielectric 1

.80 millimeters thick, with a dielectric constant of K=3.60. The resultant electric field in the dielectric is 1.20×106 volts per meter. Part A Compute the magnitude of the charge per unit area σ on the conducting plate. Express your answer in coulombs per square meter to three significant figures.
Physics
1 answer:
TEA [102]3 years ago
3 0

Answer: 38.2 μC

Explanation: In order to solve this problem we have to use the relationship for a two plate capacitor with a dielectric  so:

C= Q/V= we also know that for two paralel plates C=εo*k*A/d and V=E/d

where k is the dielectric constant, A plate area, V is potential difference; E electric field and d the separation between the plates.

reorganizing we have:

Q/A=σ= E*k/εo= 1.2 * 10^6*3.6/8.85 * 10^-12=38.2μC

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Answer: Option (a) is the correct answer.

Explanation:

Ionic compounds are the compounds whose atoms are combined together by transfer of electrons.

An ionic compound has partial positive charge on the cation and partial negative charge on anion.

For example, NaCl is an ionic compound whose atoms are arranged orderly due to the opposite charges on its atoms.

So, an ionic compound forms a neutral compound but not a neutral element.

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3 0
3 years ago
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Answer:

<em>Entropy Change = 0.559 Times</em>

Explanation:

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3 years ago
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LenaWriter [7]

Answer:

Options d and e

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L = 9.8/16

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This means only pendulum lengths in this range will oscillate.Therefore pendulums with length 0.8m and 1.2m will be strongly set in motion.

Have a great day ahead

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