Plzz!!! I need help now this is science

A class investigated the reactivity of four metals by dropping little pieces of the

Pavlova-9 [17]

The least reactive metal is lead, since it reacted with none of the salt solutions.

3 0

3 years ago

How do weathering and deposition differ?

Paul [167]

C) Weathering can be chemical or physical; deposition
is only chemical

4 0

1 year ago

Read 2 more answers

Balance the following chemical equation (with all steps)

WARRIOR [948]

Answer:

Balanced chemical equation:

2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂

Explanation:

Chemical equation:

Al + H₂SO₄ → Al₂(SO₄)₃ + H₂

Balanced chemical equation:

2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂

Steps:

Let balance the SO₄ first.

Al + 3H₂SO₄ → Al₂(SO₄)₃ + H₂

There are three H₂ on left so put the coefficient three on right too.

Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂

Two Al on right and one on left so we will put the coefficient two on left.

2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂

All atoms are correctly balanced.

3 0

3 years ago

PLSSSSS HELP I DONT GET THIS PROBLEMMMM

Aleks [24]

Answer:

C. 7370 joules.

Explanation:

There is a mistake in the statement. Correct form is described below:

Using the above data table and graph, calculate the total energy in Joules required to raise the temperature of 15 grams of ice at -5.00 °C to water at 35 °C.

The total energy needed to raise the temperature is the combination of latent and sensible heats, all measured in joules, and represented by the following model:

$Q = m\cdot [c_{i} \cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})]$ (1)

Where:

$m$ - Mass of the sample, in grams.

$c_{i}$ - Specific heat of ice, in joules per gram-degree Celsius.

$c_{w}$ - Specific heat of water, in joules per gram-degree Celsius.

$L_{f}$ - Latent heat of fusion, in joules per gram.

$T_{1}$ - Initial temperature of the sample, in degrees Celsius.

$T_{2}$ - Melting point of water, in degrees Celsius.

$T_{3}$ - Final temperature of water, in degrees Celsius.

$Q$ - Total energy, in joules.

If we know that $m = 15\,g$ , $c_{i} = 2.06\,\frac{J}{g\cdot ^{\circ}C}$ , $c_{w} = 4.184\,\frac{J}{g\cdot ^{\circ}C}$ , $L_{f} = 334.72\,\frac{J}{g}$ , $T_{1} = -5\,^{\circ}C$ , $T_{2} = 0\,^{\circ}C$ and $T_{3} = 35\,^{\circ}C$ , then the final energy to raise the temperature of the sample is:

$Q = (15\,g)\cdot \left[\left(2.06\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (5\,^{\circ}C)+ 334.72\,\frac{J}{g} + \left(4.184\,\frac{J}{g\cdot ^{\circ}C}\right)\cdot (35\,^{\circ}C) \right]$

$Q = 7371.9\,J$

Hence, the correct answer is C.

8 0

2 years ago

what blood vessels and chambers does a molecule of glucose absorbed through the gut passes on its way to an active muscle in the

posledela

Answer:

Arteries are blood vessels that generally carry oxygen rich blood AWAY from the heart and lungs to the capillaries. The walls of ... and glucose, are absorbed from the digestive system and transported to the cells. Plasma ...

4 0

3 years ago