The question is incomplete, complete question is:
When copper(I) sulfide is partially roasted in air (reaction with oxygen), copper(I) sulfite is formed first. subsequently, upon heating, the copper sulfite thermally decomposes to copper(I) oxide and sulfur dioxide. Write balanced chemical equations for these two reactions.
Answer:
The balanced chemical equations for these two reactions:
Explanation:
On partial roasting of copper sulfide in an air. The balanced chemical reaction is given as:
On further heating of copper(I) sulfite it get decomposes into copper oxide and sulfur dioxide. The balanced chemical reaction is given as:
you would change one element to a diffrent element
The addition of hydrogen carbonate to bromothymol blue turns the solution blue. Thus, option B is correct.
The balanced equation for the dissociation of bromothymol blue is:
The color of dissociated form is yellow and undissociated form is blue.
<h3>What is the final color of solution?</h3>
The addition of hydrogen carbonate results in the dissociated ions as:
The dissociation results in the increased hydrogen ion concentration. The undissociated form in the reaction mixture increases.
Thus, the color of the solution will turn blue. Hence, option B is correct.
Learn more about bromothymol blue, here:
brainly.com/question/24319054
Answer:
4.15×10⁻²¹ moles of Sn
Explanation:
This question can be solved by a simple rule of three.
We know that 1 mol contains 6.02×10²³ particles.
In this case, our particles are the atoms, so:
6.02×10²³ atoms / 1 mol . 2500 atoms = 4.15×10⁻²¹ moles.
The knowledge of mol can be applied for everything:
A mol of molecules
A mol of atoms
A mol of a compound
The tide is where the sea level rises and falls
