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Nastasia [14]
3 years ago
9

A particle that orbits the nucleus in an atom is called a(n)

Chemistry
1 answer:
horrorfan [7]3 years ago
3 0
The answer is electron
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Thirty grams of lead oxide and fifteen grams of ammonia react completely to produce solid lead, nitrogen gas, and liquid water.
Kitty [74]

45 g  Thirty grams of lead oxide and fifteen grams of ammonia react completely to produce solid lead, nitrogen gas, and liquid water.

8 0
3 years ago
Read 2 more answers
Which way would CCI2F2 orient in an electric field?
ArbitrLikvidat [17]

Answer:

See explanation

Explanation:

In looking at molecules to determine whether they are polar or not we have to look at two things basically;

i) presence of polar bonds

ii) geometry of the molecule

Now, we know that CCI2F2 is a tetrahedral molecule, but the molecule is not symmetrical. It has four polar bonds that are not all the same hence the molecule is polar.

In an electric field, polar molecules orient themselves in such a way that  the positive ends of the molecule are being attracted to the negative plate while the negative ends of the molecules are attracted to the positive plate.

So the positive ends of CCI2F2  are oriented towards the negative plate of the field while the negative ends of CCI2F2 are oriented towards the positive ends of the field.

3 0
2 years ago
I beg you to help me in this and im gonna mark u as brainliest but fassttt
Anni [7]

Explanation:

F = nucleus

G = cell membrane

H = cytoplasm

J = cell wall

k = vacoule

L = plastids

mark me brainiest?

6 0
3 years ago
Read 2 more answers
How many grams of o2 are required to produce 358.5 grams of zno? 2zn + o2 ® 2zno?
Murrr4er [49]
The balanced equation for the reaction is ;
2Zn + O2 —> 2ZnO
The stoichiometry of O2 to ZnO is 1:2
The mass of ZnO formed - 358.5 g
The number of moles formed - 358.5 g / 81.4 g/mol = 4.4 moles
Therefore number of O2 moles reacted = 4.4 moles /2 = 2.2 mol
Mass of O2 reacted = 2.2 mol x 32 g/mol = 70.4 g
6 0
3 years ago
Label the
alexandr402 [8]

Answer:

0.1 m HCI

0.001m HCI

0.00001m HCI

Distilled Water

0.0001m NaOH

0.001m NaOH

0.1m NaOH

Explanation:

7 0
3 years ago
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